Express 4x^2 − 12x in the form (2x + a)^2 + b.

A portfolio has average return of 13.2 percent and standard deviation of returns of 18.9 percent. Assuming that the portfolioi's

wlad13 [49]

Answer:

B. 0.835

Step-by-step explanation:

We can use the z-scores and the standard normal distribution to calculate this probability.

We have a normal distribution for the portfolio return, with mean 13.2 and standard deviation 18.9.

We have to calculate the probability that the portfolio's return in any given year is between -43.5 and 32.1.

Then, the z-scores for X=-43.5 and 32.1 are:

$z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{(-43.5)-13.2}{18.9}=\dfrac{-56.7}{18.9}=-3\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{32.1-13.2}{18.9}=\dfrac{18.9}{18.9}=1\\\\\\$

Then, the probability that the portfolio's return in any given year is between -43.5 and 32.1 is:

$P(-43.5$

6 0

2 years ago

A package delivery service divides their packages into weight classes. suppose that packages in the 14 to 20 pound class are uni

nexus9112 [7]

Answer: $yy - \alpha \alpha = Percentile (\beta \beta -\alpha \alpha )$

$yy = 0.40 (20 - 14) + 14[tex] yy = 2.4 + 14$

$yy = 16.4$

Thus, 16.4 pound class belongs to the 40th percentile of the weight class.

6 0

2 years ago

On 1st September 2014 there were 5400 trees planted in a wood.

Aliun [14]

Answer:

1. a = 5400

2. r = 0.96

3. Percentage decrement = 65.4%

Step-by-step explanation:

Given

N = ar^t

Solving (a): Write down the value of a

a implies the first term

And from the question, we understand that the initial number of trees is 5400.

Hence,

a = 5400

Solving (b): Show that r = 0.96

Using

N = ar^t

When a = 5400, t = 1 i.e. the first year and N = 5184

Substitute these values in the above expression

5184 = 5400 * r¹

5184 = 5400 * r

5184 = 5400r

Solve for r

r = 5184/5400

r = 0.96

Solving (c): Show that the trees has decreased by over 65% in 2040

First, we need to calculate number of years (t) in 2040

t = 2040 - 2014

t = 26

Substitute 26 for t, 5400 for a and 0.96 for r in N = ar^t to get the number of trees left

N = 5400 * 0.96^26

N = 1868.29658019

N = 1868 (approximated)

Next, we calculate the percentage change as thus:

%Change = (Final - Initial)/Initial * 100%

Where the initial number of trees =5400 and final = 1868

%Change = (1868 - 5400)/5400 * 100%

%Change = -3532/5400 * 100%

%Change = -3532%/54

%Change = -65.4%

The negative sign indicates a decrements or reduction.

Hence, percentage decrement = 65.4% and this is over 65%

3 0

1 year ago

You are given a rectangular sheet of cardboard that measures 11 in. by 8.5 in. (see the diagram below). A small square of the sa

GaryK [48]

Answer:

Terrence's

Step-by-step explanation:

The length of the square that will be cut out is the height of the box.

1. a

Anya's method: 8.5 -1.5 =7, 11- 1.5 =9.5, the height is 1.5, so the volume is height x length x width which is 1.5 x 9.5 x 7 =99.75 squared inches.

Terrence's method: 8.5-3 = 5.5, 11-3 = 8. Vol= 5.5 x 8 x 3 =132 squared inches. 99.75 < 132 squared inches, Terrence's idea would create larger volume.

1. b

The box's size depends on the length/width/height of the cardboard being cut, which is why different measurements / cutting methods for the same size cardboard can result in different box sizes.

2. The square would be cut from all four corners, therefore the sum of the 2 squares on the cardboard cannot exceed the short side of the cardboard. The shorter side of the cardboard is 8.5 inches, divided by 2 = 4.25 inches, hence the squares cannot be larger than 4.25 inches. Keep in mind that if you cut exactly 4.25 inches you will have a strip of 2.5 inches width that cannot be turned into a box.

If you want to cut 5 inches squares out, depending on how you draw it, it would either overlap or go outside of the paper because 5+5 is ten, surely on the 11 inches side that would still be perfectly fine but for the 8.5 inches side, there isn't any room for the 10 inches.

7 0

2 years ago

Pete is conducting a survey to determine his customers’ overall satisfaction about the quality of his company’s products. He sen

hram777 [196]

No.
Because, when to do some sort of analysis (such as this one), you need to take (for example) a RANDOM SAMPLE from the POPULATION of the problem that is being analyzed. In this example (problem), Pete wants to evaluate OVERALL satisfaction of customers, so he should NOT send the surveys ONLY to the customers who have purchased the LARGEST number of items, but to the randomly selected customers, in order to obtain REPRESENTATIVE results of the OVERALL satisfaction. If he sends the surveys only to the customers who have bought the largest number of items, he will obtain VERY HIGH satisfaction of customers, as results, of course, and this will not be representative results.

8 0

2 years ago

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