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suter [353]
1 year ago
6

the length of the rectangle is measured as 370mm correct to 2 significant figures.a) what is the upper bound for the length?the

width of this rectangle is measured as 19.4mm correct to 1 decimal place.b) what is the lower bound for the area of the rectangle?
Mathematics
1 answer:
ivanzaharov [21]1 year ago
7 0

Answer:

a) 375

b) 7062.75 mm²

Step-by-step explanation:

b) We need to find the shortest possible width and length to get the smallest possible area.

To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.

The boundaries are, therefore: 19.35 - 19.45

As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.

And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:

365 * 19.35 = 7062.75 mm²

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What is the completely factored form of p4 - 16?
il63 [147K]

The completely factored form of p^4-16 is:

(p^2+4)(p+2)(p-2)

Step-by-step explanation:

We have to factorize the given expression to get the final result

Given

p^4-16\\Using\ Formula: a^2-b^2=(a+b)(a-b)\\(p^2)^2-(4)^2\\=(p^2+4)(p^2-4)

p^2-4 can further be factored again

=(p^2+4)[(p)^2-(2)^2]\\=(p^2+4)(p+2)(p-2)

The completely factored form of p^4-16 is:

(p^2+4)(p+2)(p-2)

Keywords: Factorization

Learn more about factorization at:

  • brainly.com/question/9323337
  • brainly.com/question/9381080

#LearnwithBrainly

8 0
2 years ago
In circle M shown, chords GH and EF intersect at K such that EK  5 and FK  6 . If GK  3 , then which of the following is the
myrzilka [38]

The length of the GH segment is 13  

Step-by-step explanation:

For solving this problem we need to remember some of the circle corollaries-

When two-chord intersects each other, the product of the chord segments are equal

The above corollary can be easily understood by looking at a diagram attached below-

In the figure, EF and GH are two chords intersecting at K

Thus, EK*KF= GK*KH

Values of the EK, KF, GK are given as 5, 6 and 3 respectively

Substituting the values we get

5*6=3*KH

KH= 10

We know that GH= GK+KH

Thus GH= 3+10= 13

6 0
2 years ago
The 8th term of a GP is -7/32 find its common ratio if its first term is 28
Ugo [173]
<h2>Common ratio = -1/2</h2>

Step-by-step explanation:

       \text{8}^{th} term of a Geometric progression is given as \dfrac{-7}{32}. The first term is given as 28.

       Any general Geometric progression can be represented using the series a,ar,ar^{2},ar^{3},ar^{4}...\text{ }ar^{n-1}.

The first term in such a GP is given by a, common ratio by r, and the n^{th} term is given by ar^{n-1}.

       In the given GP, a=28;t_{8}=ar^{7}=\dfrac{-7}{32}\\\\28r^{7}=\dfrac{-7}{32}\\\\r^{7}=\dfrac{-1}{128}\\\\r=\dfrac{-1}{2}

∴ Common ratio is \dfrac{-1}{2}.

5 0
2 years ago
Write the number that can be shown with this many hundreds tens and ones 1 2 18
NISA [10]
Maybe is 2181 the biggest 
6 0
2 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
GalinKa [24]

Answer:

Jada should have multiplied both sides of the equation by 108.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:

Step 1: Multiply both sides of the equation by -9/4 as shown:

-4/9 × -9/4 = x/108 × -9/4

-36/-36 = -9x/432

1 = -9x/432

1 = -x/48

Cross multiplying

48 = -x

x = -48

It can also be solved like this:

Given -4/9 = x/108

Multiply both sides by 108 to have:

-4/9 * 108 = x/108 * 108

-4/9 * 108 = 108x/108

-432/9 = x

x = -48

Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.

7 0
2 years ago
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