Jonny is writing a program for a video game. For one part of the game he uses the rule given below to move objects on the screen
2 answers:
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Hello,
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
Given:
Area of rectangle =
Width of the rectangle is equal to the greatest common monomial factor of .
To find:
Length and width of the rectangle.
Solution:
Width of the rectangle is equal to the greatest common monomial factor of is
Now,
So, width of the rectangle is .
Area of rectangle is
Taking out GCF, we get
We know that, area of a rectangle is the product of its length and width.
Since, width of the rectangle is , therefore length of the rectangle is
.