Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
Answer
this is hard
explanation
sorry i can’t answer i’m bad at math
Answer: We are given:

We need to find the z scores for the following vacation expense amounts:
$197, $277, $310
We know that z score formula is:

When
, the z score is:



When
, the z score is:



When
, the z score is:



Therefore, the z scores for the vacation expense amounts $197 per day, $277 per day, and $310 per day are -0.83, 0.5 and 1.05 respectively
Answer: Check the attached
Step-by-step explanation: