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Triss [41]
2 years ago
5

Calculate the change in enthalpy for Reaction 2.

Chemistry
2 answers:
seropon [69]2 years ago
7 0
 Best Answer:<span>  </span><span>Sorry its kind of hard to explain, you just need to study hesslaw, practice makes perfect, keep studying! 
A. REACTION 2 IS MULTIPLIED BY 3 (HESS LAW) 
ΔH2= -6129 j 
B. IF REACTION IS REVERSED YOU FLIP THE SIGN OF ΔH 
ΔH = 92.3 kJ 
C. KIND OF HARD TO EXPLAIN, BUT I CAN TRY AND SHOW YOU 
EQUATION 1 (FLIP) CH4 --> C + H2 
EQUATION 4 (FLIP AND MULTIPLY BY 2) H2O(g) --> H2O(l) 
ΔH = -890.7</span>
Oduvanchick [21]2 years ago
3 0

[3 mol CO2(g) + 4 mol H2O(g)] - [1 mol C3H8(g) + 5 mol O2(g)]

[3 · (213.74 J/mol·K) + 4 · (188.825 J/mol·K)] - [1 · (269.9 J/mol·K) + 5 · (205.138 J/mol·K)]

=100.93 J/mol·K

Answer: 100.93 J/mol·K

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What is the limiting reactant for the reaction below given that you start with 10.0 grams of Al (molar mass 26.98 g mol-1) and 1
mezya [45]

Answer:

Al

Explanation:

4 Al  +  3 O₂  →  2 Al₂O₃

You need to figure out which one has the smaller mole ratio.  Convert both substances from grams to moles.

(10.0 g Al)/(26.98 g/mol) = 0.3706 mol Al

(19.0 g O₂)/(32.00 g/mol) = 0.5938 mol O₂

Now, use the mole ratios of reactant to product to see which substance produces the least amount of product.

(0.3706 mol Al) × (2 mol Al₂O₃/4 mol Al) = 0.1853 mol Al₂O₃

(0.5938 mol O₂) × (2 mol Al₂O₃/3 mol O₂) = 0.3958 mol Al₂O₃

Since aluminum produces the least amount of product, this is the limiting reagent.

4 0
2 years ago
what is the new pressure acting on a 2.5 l balloon if its original volume was 5.8 l at 3.7 ATM of pressure
Ivan

Answer : The new pressure acting on a 2.5 L balloon is, 8.6 atm.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

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P_1V_1=P_2V_2

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P_1 = initial pressure = 3.7 atm

P_2 = final pressure = ?

V_1 = initial volume = 5.8 L

V_2 = final volume = 2.5 L

Now put all the given values in the above equation, we get:

3.7atm\times 5.8L=P_2\times 2.5L

P_2=8.6atm

Thus, the new pressure acting on a 2.5 L balloon is, 8.6 atm.

8 0
2 years ago
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VARVARA [1.3K]
Check attached file for the answer.

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Mass in grams of 6.25 mol of copper (II) nitrate?
podryga [215]
Cu = 63.546
N= 14.001 g/mol
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6.25 x 125.544

= 784.65 <--- is your answer, if there were was a multiple choice or not :)
8 0
2 years ago
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Explain how manipulation of light waves can cause reflection, refraction, diffusion, and absorption; and describe how different
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