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2 years ago

A solid element that is malleable' a good conductor of electricity, and reacts with oxygen is classified as a

1 answer:

5 0

1) metal
Even though metalloids are also conductors of heat and electricity, malleable they are not as good as metals.
Metals are very good conductors of electricity and heat. They are also very hard to touch. Noble gases and non metals are the exact opposite in physical and chemical properties. Metals readily react with oxygen.

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Not too long ago houses were protected from excessive currents by fuses rather than circuit breakers. sometimes a fuse blew out

olganol [36]

Answer: Resistance = $8.21 \times 10^{-8} \Omega$

The approximate diameter of a penny is, d = 20 mm

thickness of penny is, L = 1.5× $10^{-3}$ mm

The area of penny along circular face is, $A = \frac{\pi d^2}{4} =\frac{\pi (20 mm\frac{1 m}{1000 m})^2}{4}$

= 3.14× $10^{-4}$ m²

The resistivity of copper is ρ = 1.72 x 10-8 Ωm.

Resistance,

$R = \rho \frac{L}{A} = (1.72 \times 10^{-8} \Omega m)\frac{1.5 \times 10^{-3} m}{3.14 \times 10^{-4} m^2} = 8.21 \times 10^{-8} \Omega$

5 0

2 years ago

You are boiling pasta and absentmindedly grab a copper stirring spoon rather than your wooden spoon. The copper spoon has a 20 m

11111nata11111 [884]

The spoon to transfer 40 J of energy to your hand is descibed as follows

Explanation:

Given area of cross section of copper spoon is A = 20mm into 1.5 mm

temperature difference is DT = (100 minus 35) = 65 0C

length of the spoon is l = 18 cm,

amount of heat should be transfer Q = 40 J

coefficient of thermal conductivity of copper k = 400 W by mk

we know that the thermal conductivity is Q by t = k into A into DT by l

t = Q into l by k into A into DT

t = (40 into 0.18) by $\left(400 \times 30 \times 10^{-6} \times 65\right)$

t = 9.23 s

6 0

2 years ago

A violin with string length 32 cm and string density 1.5 g/cm resonates in its fundamental with the first overtone of a 2.0-m or

love history [14]

Answer:

T=1022.42 N

Explanation:

Given that

l = 32 cm ,μ = 1.5 g/cm

L =2 m ,V= 344 m/s

The pipe is closed so n= 3 ,for first over tone

$f=\dfrac{nV}{4L}$

$f=\dfrac{3\times 344}{4\times 2}$

f= 129 Hz

The tension in the string given as

T = f²(4l²) μ

Now by putting the values

T = f²(4l²) μ

T = 129² x (4 x 0.32²) x 1.5 x 10⁻³ x 100

T=1022.42 N

6 0

2 years ago

A block is projected with speed v across a horizontal surface and slides to a stop due to friction. The same block is then proje

natka813 [3]

Answer: C. The case on the inclined surface had the least decrease intotal mechanical energy.

Explanation:

First and foremost, it should be noted that the mechanical energy is the addition of the potential and the kinetic energy.

From the information given, it should be known that when the block is projected with the same speed v up an incline where is slides to a stop due to friction, the box will lose its kinetic energy but there'll be na increase in the potential energy as a result of the veritcal height. This then brings about an increase in the mechanical energy.

Therefore, the total mechanical energy of the block will decrease the least when the case on the inclined surface had the least decrease intotal mechanical energy.

8 0

1 year ago

The position of an object that is oscillating on an ideal spring is given by the equation x=(12.3cm)cos[(1.26s−1)t]. (a) at time

Natali5045456 [20]

x=((12.3/100)m)cos[(1.26s^−1)t]
v= dx/dt = -((12.3/100)*1.26)sin[(1.26s^−1)t]
v=-((12.3/100)*1.26)sin[(1.26s^−1)t]=-((12.3/100)*1.26)sin[(1.26s^−1)*(0.815)]
v= -0.13261622 m/s
the object moving at 0.13 m/s at time t=0.815 s

6 0

2 years ago