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mestny [16]
2 years ago
4

A random sample of people is chosen to participate in a survey. For the survey results to be considered valid, which must be tru

e of the random sample? The sample must be the same size as the population. The sample must represent the target population. The sample must be biased. The sample must be a group separate from the population.
Mathematics
2 answers:
wariber [46]2 years ago
6 0
The sample must represent the target population 
Shtirlitz [24]2 years ago
3 0

Answer:

B

Step-by-step explanation:

Right on Edg.

uwu :0)

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Find all the zeros of the equation<br> -2x^4+27x^2+1200=0
Angelina_Jolie [31]
For this case we have the following polynomial:
 -2x ^ 4 + 27x ^ 2 + 1200 = 0
 To solve the problem we apply the following steps:
 1) We make a change of variables u = x ^ 2
 2) We rewrite the polynomial
 3) Solve the quadratic equation using the formula for the quadratic equation
 4) We return the change and find four roots
 Answer:
 
See attached image for procedure and solution

4 0
2 years ago
Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0
2 years ago
A process engineer is implementing a quality assurance system on a breakfast cereal production line. A new sensor is installed o
nataly862011 [7]

Answer:

0.2%

Step-by-step explanation:

The given parameters are;

The percentage of product within the correct range = 95%

The percentage of the times the sensor reject boxes of incorrect weight = 98%

The percentage of the times the company reject boxes with correct weight = 1%

\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776

The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%

The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

5 0
2 years ago
You work delivering food for a local farmer. You sell onions from the farm at these prices: 2 for $1.04, 4 for $2.52, 8 for $4.3
kenny6666 [7]

Answer:

D.  9%

Step-by-step explanation:

1.04 / 2 = 0.52

2.52 / 4 = 0.63    best 1

4.32 / 8 = 0.54

9.12 / 16 = 0.57    best 2

if base on the best deal 1 - 0.63

(0.63 - 0.57) / 0.63 = 0.0952  (≈ 0.09 i.e 9%)

8 0
2 years ago
Madison randomly surveyed 50 students at her high school about their favorite color, and 18 students chose blue. Madison conclud
Aleks04 [339]
Should be A, if not then prolly B
4 0
2 years ago
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