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maksim [4K]
2 years ago
5

10. Triangle PQR has vertices P(5, -1), Q(0, 8), and R(7, 5). It is translated right 3 units and up 6 units. Find the coordinate

s of P', Q', and R'.
Mathematics
1 answer:
Brrunno [24]2 years ago
3 0
P' (8,5)
Q' (3,14)
R' (10, 11)

Why: Anything that is translated left or right you will be changing the x axis,  if the translation is right, you add, if its left, you subtract. If the translation is up or down, its going to change the y axis. Down means you subtract from the y axis, up means you add to the y axis. 
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Jessica deposits $5,000 at the end of each year in an account earning 2.45% interest, compounded annually. What is the future va
denpristay [2]
Hi there
If the amount deposited at (end) of each year, use the formula of the (future/present) value of annuity ordinary

If the amount deposited at the (beginning) of each year use the formula of the (future/present) value of annuity due

So
FvAo=5,000×(((1+0.0245)^(5)−1)
÷(0.0245))
=26,255.38...answer

Hope it helps

8 0
1 year ago
what is the value of the constant in the equation that relates the height and width of this rectangle
Doss [256]

The correct answer is C. 1.5

You can find this answer by using any of the points on the graph and putting them into the given equation. Then you can solve for the constant. For the purpose of this example, we will use (10, 15)

Height = Constant * Width ---> Plug in known values.

15 = Constant * 10 ----> Divide both sides by 10

1.5 = Constant

This will work with whatever numbers you use from the graph. Although this graph does not have any others to really choose from.

8 0
1 year ago
What is the greatest common factor of x2y and xy2 ?
Bond [772]
GCF of :2xy and 2xy
   

2(x+y)

5 0
1 year ago
A rectangle that is x feet wide is inscribed in a circle of radius 25 feet. Express the area of the rectangle as a function of x
Viefleur [7K]

Answer:

A(x)=x(\sqrt{2500-x^{2} } ) is the area expressed as function of x,

and x: >0, <50 is the domain of the function.

Step-by-step explanation:

Draw an appropriate figure and then express the area of the rectangle as a function of x.

We know that the diagonal of a rectangle inscribed in a circle, will be equal to the diameter of the circle. 50 feet

let w = the width of the rectangle

therefore

x^2 + w^2 = 50^2\\w^2 = 2500 - x^2\\w = \sqrt{2500-x^{2} }

recall

Area = x*w

replace w

A(x)=x(\sqrt{2500-x^{2} } ) is the area expressed as function of x

b)state the domain of the function

x: >0, <50

7 0
2 years ago
On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne
nasty-shy [4]

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are (x_{1},y_{1})  and  (x_{2},y_{2})  then,

  • x=\frac{x_{1}+x_{2}}{2}
  • y=\frac{y_{1}+y_{2}}{2}

In a parallelogram, its diagonals intersect each other at their mid-points

that means its diagonals bisect each other

∵ HIJK is a quadrilateral

∵ HJ and IK are its diagonals

∵ H = (-2 , 2)

∵ J = (4 , -2)

- Find the mid point of HJ  

∵ M_{HJ}=(\frac{-2+4}{2},\frac{2+-2}{2})

∴ M_{HJ}=(\frac{2}{2},\frac{0}{2})

∴ M_{HJ}=(1,0)

∴ The mid-point of HJ is (1 , 0)

∵ I = (4 , 3)

∵ K = (-2 , -3)

- Find the mid point of IK  

∵ M_{IK}=(\frac{4+-2}{2},\frac{3+-3}{2})

∴ M_{IK}=(\frac{2}{2},\frac{0}{2})

∴ M_{IK}=(1,0)

∴ The mid-point of IK is (1 , 0)

∵ The mid-points of HJ and IK are equal

∴ HJ and IK bisects each other

∴ HIJK is a parallelogram because its diagonals bisect each other

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Learn more:

You can learn more about parallelogram in brainly.com/question/6779145

#LearnwithBrainly

6 0
1 year ago
Read 2 more answers
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