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2 years ago

The surface area of a swimming pool is 373 square feet. What is it’s surface area in square meters?

Mathematics

1 answer:

jeka57 [31]2 years ago

6 0

The surface area of swimming pool is 373 square feet .

In this question, we have to convert square feet to square meters, that is

$1 feet = 0.3048 meter$

Squaring both sides ,

$1 feet^2 = 0.3048^2 meter^2$

$1 feet ^2 = 0.09290304 meter^2$

And

$373 feet^2 = 373* 0.09290304 meter^2$

$373 feet^2= 34.653meter^2$

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A card is drawn from a deck of cards numbered one through twenty. The card is NOT replaced and another card is drawn. Find the p

Bess [88]

Answer:

B) P(two prime numbers are drawn in a row) = 14/95

Step-by-step explanation:

Total cards in the deck = 20

Total prime numbered cards in deck = { 2, 3, 5, 7, 11, 13, 17, 19} = 8 cards

So, Probability of picking two prime cards from deck (without replacing)

= Probability of picking first prime card x Probability of picking second prime card

P( picking first prime card ) = $\frac{\textrm{Total prime cards in the deck}}{\textrm{Total available cards}}$

= $\frac{8 }{20} = \frac{2}{5}$

P( picking second prime card ) = $\frac{\textrm{Total prime cards in the deck}}{\textrm{Total available cards}}$

= $\frac{7}{19}$

Hence, the total probability = $\frac{2}{5} \times \frac{7}{19} = \frac{14}{95}$

or, B) P(two prime numbers are drawn in a row) = 14/95

4 0

1 year ago

1) Proiectiile catetelor unui triunghi dreptunghic pe ipotenuza au lungimile 9 cm si 25 cm. Aflati lungimea inaltimii din varful

Flauer [41]

Answer:

1) 15cm

2) left projection/h = h/right projection

Step-by-step explanation:

Question:

1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.

2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.

Solution

1) The length of the height of a right angle triangle is also called the altitude.

Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.

The projections of the legs are 25cm and 9cm.

Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm

In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the

geometric mean of these two segments (the two projections) and it's given by:

left projection/h = h/right projection

AD/h = h/DB

25/h = h/9

Cross multiply

h^2 = 25×9

h =√225 = 15cm

The length of the height at the top of the triangle = 15cm

2) Length of hypotenuse = 34

From the question, the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75.

There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.

To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.

left projection/h = h/right projection

To find each leg using question 1 above, each leg of the triangle is the mean proportional between the hypotenuse and the part of the hypotenuse directly below the leg.

Hypotenuse =34cm

Hyp/leg = leg/part

To find leg y, part for leg y = 25cm

34/y = y/25

y^2 = 34×25 = 850

y = √850 = 29.2cm

To find leg x, part for leg x = 9cm

34/y = y/9

y^2 = 34×9 = 306

y = √306 = 17.5cm