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Helga [31]
2 years ago
6

What is a fraction that is equivalent to 0.997

Mathematics
2 answers:
Stels [109]2 years ago
5 0
997/1000 hope this helps
Paul [167]2 years ago
3 0
.997 = \frac{997}{1000}
It can't be simplified any more than that so that is your final answer.

Hope that helps.
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Answer below these questions
timurjin [86]

Answer:

A: 6x⁸y⁵

B: 4x⁵z⁸

C: 48a¹²b⁵

D: 6s⁹t³

Step-by-step explanation:

When you multiply 2 exponents together, you add them. When you power an exponent, you multiply the 2 exponents together,

3x²2y⁴(2x⁶y)

6x⁸y⁵

xz³(4x⁴z⁵)

4x⁵z⁸

(4a³)²(3a⁶b⁵)

16a⁶(3a⁶b⁵)

48a¹²b⁵

6s⁵t(s⁴t²)

6s⁹t³

3 0
2 years ago
You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In
alexandr1967 [171]
C.  $360


$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)
4 0
2 years ago
Read 2 more answers
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
Pam is looking for a new car. She has test-driven two cars but can only purchase one. The probability that she will purchase car
gulaghasi [49]

Answer:

0.80

Step-by-step explanation:

7 0
1 year ago
Harvie buys one notebook for $1. 59 and pens for $0. 29 each. He spends a total of $5.07 Assume there is
Andre45 [30]

Answer:

0.29p + 1.59 = 5.07 where p represents the number of pens

Step-by-step explanation:

5 0
2 years ago
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