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lara [203]
1 year ago
9

Joe wants to enlarge the rectangular pumpkin patch located on his farm. The pumpkin patch is currently 40 meters wide and 60 met

ers long. The new pumpkin patch will be 3x meters wider and 5x meters longer than that of the original pumpkin patch. Which of the following functions will give the area of the new pumpkin patch in square meters?
Mathematics
1 answer:
den301095 [7]1 year ago
8 0

Answer:

The area of new pumpkin patch is  Area_2  =  15 x² + 380 x + 2400

Step-by-step explanation:

Given as :

The length of rectangular patch = L = 40 meters

The width of rectangular patch = W = 60 meters

So, The area of rectangular patch = Length × Width

Or, Area_1 =  L × W

So ,  Area_1  =  40 meters × 60 meters

Or,  Area_1 =  2400 meters²

Again The Width of new Patch = ( 40 + 3 x ) meter

And     The Length of new Patch = ( 60 + 5 x )  meter

Or, Area_2  =  L × W

So ,Area_2  =  ( 40 + 3 x ) meters × ( 60 + 5 x ) meters

Or,  Area_2  = 2400 + 200 x + 180 x + 15 x²

Or,  Area_2  =  15 x² + 380 x + 2400

Hence The area of new pumpkin patch is  Area_2  =  15 x² + 380 x + 2400  Answer

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A student wants to know how far above the ground the top of a leaning flagpole is. At high​ noon, when the sun is almost directl
MariettaO [177]

Answer:

15.43 ft

Step-by-step explanation:

To solve this question, one should use the concept of similar triangles.

The pole's shadow and the distance to the ground (x) form a similar triangle to the distance of the plumb bob from the base and the length of the plumb bob, respectively. Note that we do not need to know the measurements of the third side of the triangles to solve the problem.  Therefore, the distance of the top of the pole to the ground is:

14 in = 1.1667 ft

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The distance of the top of the pole to the ground is 15.43 ft.

4 0
1 year ago
The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3
viva [34]

Answer:

119.45 m

Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

\triangle ABC represents the 1st angle of elevation of sun i.e.  58°

\triangle ABD represents the 2nd angle of elevation of sun i.e.  36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = h m

Let side BC = x m

Now, let us apply tangent rules in \triangle ABC, \triangle ABD one by one:

tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)

tan36^\circ = \dfrac{h}{x+90}

Putting value of x using equation (1):

tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}

119.45 m is the height of pole.

7 0
2 years ago
2527=3<br>3214=8<br>1249=4<br>7321=?<br>A)7 B)3 C)9<br>​
tester [92]

Answer:

c) 9

Step-by-step explanation:

7321=9

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The original price of an item plus a sales tax of 8.5%
dusya [7]
It depends on What the original item is.
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2 years ago
What relation does not have an initial value of 50
Mamont248 [21]
I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

4 0
2 years ago
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