Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Answer:
-1.1 cups
Step-by-step explanation:
To find out how much was spent on the main bottle of detergent, we must add the expenses that were incurred in the wash.
The statement tells us that first there is an expense of 0.4 cups of laundry detergent while washing one load of laundry and 0.7 coupon another load, therefore this means that the change in the bottle would be:
(-0.4) + (-0.7) = -0.4 - 0.7 = -1.1 cups.
In other words, the main bottle would have 1.1 cups less, that is, -1.1 cups.
Let the side of one square be x. Area = x*x = x²
Then the side of other square would be 2x , Area = 2x*2x = 4x²
Combined area = x² + 4x² = 5x²
This combined area = 45 cm²
Therefore 5x² = 45 Divide both sides by 5
x² = 45/5
x² = 9 Take square root of both sides
x = √9
x = 3
Length of larger square is 2x = 2*3 = 6 cm
Length of larger square = 6cm
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :

Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)

The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Study the figure attached below:
Answer:
240951.33km
Step-by-step explanation:
For this type of question first we need to draw the figure as shown in the attached file (Figure.1).
Looking at the figure, we can see that triangle ABC is formed by bisecting the angle 35 degree (i.e. if the angle is bisected, it will divide into two equal parts, so 35 degree will divide into two equal parts of 17.5 degree).
As the triangle ABC is a right triangle, so we can use the trigonometric ratios to find the diameter of the sun.

In the triangle ABC, perpendicular (opposite side to
) is BC and base (Adjacent side) is AC

=17.5 degree
AC=382100km
Putting the values, we get

Diameter=d=2*Radius
As BC is the distance from center of the sun, it is the radius, so we can find the diameter if we multiply it by 2.
Diameter of the sun=d=2*120475.66km
