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2 years ago

If A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4) form two line segments, and , which condition needs to be met to prove ?

Mathematics

2 answers:

MatroZZZ [7]2 years ago

7 0

The Answer is C

Step-by-step explanation:

Xelga [282]2 years ago

5 0

The answer
the full question is
If A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4) form two line segments, and AB ⊥ CD, which condition needs to be met to prove AB ⊥ CD?

let be A(x1, y1)B(x2, y2) the first line, and C(x3, y3) D(x4, y4) the second

the slope of the first line is m = y2 -y1 / x2 - x1
the slope of the second line is m' = y4 -y3 / x4 - x3

so the condition needs to be met to prove AB ⊥ CD is

y2 -y1 y4 -y3
m x m' = --------- x ------------ = -1
x2 - x1 y4 -y3

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2 years ago

Sean and his sister, Betty equally mow 8/9th the total area of a lawn. What fraction of the total area did each of them mow? (Sh

Alexxx [7]

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2 years ago

A hockey coach recorded the number of shots taken by the home team and the number taken by the visiting team in 20 games. He dis

Harrizon [31]

Answer:

The most accurate inference from this boxplot is that: The visiting team had more variability in the number of shots taken.

Step-by-step explanation:

The box and whiskers plot is a way of presenting data that gives 5 major information about the distribution

From the whiskers of the plot, one can read

- The minimum value

- The maximum value

Then, from the boxplot, one can read

- The Median, represented by the middle line of the boxplot.

- The first Quartile or 25th percentile, represented by the lower end of the boxplot.

- The third quartile or 75th percentile, represented by the upper end of the boxplot.

Other variables that can be obtained from these five data points include

- The range of the distribution (maximum value minus minimum value)

- The interquartile range (a measure of variation, which is the difference between the third and first quartile of the distribution)

For the two boxplots that the coach made

Home team

Whiskers range from 16 to 32

Minimum value = 16

maximum value = 32

the box ranges from 20 to 23. A line divides the box at 22.

First quartile = 20

Third quartile = 23

Median = 22

IQR = 23 - 20 = 3

For the visiting team

Whiskers range from 14 to 32

Minimum value = 14

maximum value = 32

the box ranges from 16 to 24. A line divides the box at 18.

First quartile = 16

Third quartile = 24

Median = 18

IQR = 24 - 16 = 8

Since the median only represents the midpoint of the distribution, one cannot conclude with certainty that home team took more shots than the visiting team, information on the mean would confirm that.

A less controversial and evident inference is that the visiting team had more variability in their shots as their distribution has a higher Interquartile Range (IQR of 8 > 3) which is a direct measure of variation for distributions.

Hope this Helps!!!

7 0

2 years ago

Read 2 more answers

A study was conducted to determine the percent of children that want to grow up work in the same career as a parent. In a sample

Irina-Kira [14]

Answer:

Step-by-step explanation:

From the information given,

Number of sample, n = 200

Probability of success, p = 43/100 = 0.43

q = 1 - p = 1 - 0.43

q = 0.57

For a confidence level of 95%, the corresponding z value is 1.96.

The formula for determining the error bound for the proportion is

z × √pq/n

= 1.96 ×√(0.43 × 0.57)/200

= 1.96 × 0.035 = 0.0686

The upper boundary of the population proportion is

0.43 + 0.0686 = 0.5

The lower boundary of the population proportion is

0.43 - 0.0686 = 0.4

The error in the solution is

phat = 0.43/200 = 0.00215

Also,

[-0.0043, 0.0086] is wrong

5 0

2 years ago

The speed of light is about 1.86×10^5 miles per second. The star Sirius is about 5.062×10^13 miles from Earth. About how many se

marysya [2.9K]

Answer:

2.72 × 10^8 seconds

Step-by-step explanation:

1. Organize the given information to help you create the equation:

- Light travels 1.86 × 10^5 miles per 1 second

- Light travels 5.062 × 10^13 miles per n seconds

- Need to solve for n

2. Set up the equation (Make sure that both numerators and both denominators match units, so the seconds are either both on top or both on bottom, NOT switched):

$\frac{1.86 * 10^5}{1}$ = $\frac{5.062 * 10^1^3}{n}$

3. Cross multiply (Multiply the first fraction's numerator by the second's denominator, and vice versa. It doesn't matter what number is on which side of the = sign)

n × (1.86 × 10^5) = 5.062 × 10^13

4. Solve for n by isolating the variable and dividing.

$\frac{n (1.86 * 10^5)}{1.86 * 10^5}$ = $\frac{5.062 * 10^1^3}{1.86 * 10^5}$

n = $\frac{5.062 * 10^1^3}{1.86 * 10^5}$

n = 2.72 × 10^8 (Make sure to include the unit, seconds)

4 0

2 years ago