Answer:
Hogan Personality Inventory
Explanation:
The Hogan Personality Inventory (HPI) is commonly used to predict job performance by measuring normal personality dimensions. It is specially used to measure certain specific traits and abilities: leadership and planning. It is based on the Five-Factor Model and was specifically developed for working adults in the business industry.
It is part of the Hogan Assessment tests used to predict job performance.
Answer: E. 18,000
Explanation:
Wesley Corporation has 80,000 shares of common stock authorized. This the total amount of common stock that is available for sale by the company.
Only 50,000 shares of common stock were issued and 12,000 shares of common stock as held as treasury stock.
Then the total number of outstanding shares of Wesley Corporation amounts to 80,000 - 50,000 - 12,000 = 18,000
Answer:
1. February – Budgeted direct labor hours = 378; Budgeted direct labor cost = $3,024.
2. March – Budgeted direct labor hours = 413; Budgeted direct labor cost = $3,304.
Explanation:
1. February direct labor budget:
a. Number of direct labor-hours budgeted for February = 0.07 * 5,400 = 378 labor hours
b. February budgeted direct labor cost = 378 * $8.00 = $3,024
2. March direct labor budget:
a. Number of direct labor-hours budgeted March = 0.07 * 5,900 = 413 labor hours
b. March budgeted direct labor cost = 413 * $8.00 = $3,304.00
Answer:
True.
Explanation:
Consumer Credit Protection Act is a law of United Stated which was enacted in 1968. This act protects the consumer against the lenders. This law set out how credit is managed on the purchases of consumer.
National City Bank has confused Simone by briefing about several mortgages and penalties of the loan. Simone is unable to identify whether mortgage loan is better option or she should consider other banks. This has violated the Consumer Credit Protection Act.
Answer:
(a) 
(b) 
(c) X=4.975 percent
Explanation:
(a) Find the z-value that corresponds to 5.40 percent
.
Hence the net interest margin of 5.40 percent is 2.5 standard deviation above the mean.
The area to the left of 2.5 from the standard normal distribution table is 0.9938.The probability that a randomly selected U.S. bank will have a net interest margin that exceeds 5.40 percent is 1-0.9938=0.0062
(b) The z-value that corresponds to 4.40 percent is 
The net interest margin of 4.40 percent is 0.5 standard deviation above the mean.
Using the normal distribution table, the area under the curve to the left of 0.5 is 0.6915
Therefore the probability that a randomly selected U.S. bank will have a net interest margin less than 4.40 percent is 0.6915
(c) The z-value that corresponds to 95% which is 1.65
We substitute the 1.65 into the formula and solve for X.
A bank that wants its net interest margin to be less than the net interest margins of 95 percent of all U.S. banks should set its net interest margin to 4.975 percent.
