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2 years ago

Use a calculator to find the approximate value of cos-1(0.45)

1 answer:

6 0

Based on the given instruction, the answer to the question can be answered straight forward using a scientific calculator. To evaluate, directly press in the shift cosine followed by 0.45, then it will give the answer of 63.26. This value is in degree.

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The erea of a square is given by x2, where x is the length of one side. Mary's original garden was in the shape of a square. She

crimeas [40]

Answer: The expression that represents the area of Mary's new garden =2x^2

Step-by-step explanation:

The area of a square is given by x^2, where x is the length of one side. The length of the other side is also x. In a square, all sides are equal. each of the four sides equal x

Area = x × x

Area = x^2

She decided to double the area of her garden

New area = 2(x × x)

New area = 2x^2

The expression that represents the area of Mary's new garden =2x^2

7 0

2 years ago

Which graph shows the solution to the system of linear inequalities? y > Two-thirdsx + 3 y ≤ Negative one-thirdx + 2

masya89 [10]

Answer:

The solution in the attached figure

Step-by-step explanation:

we have

$y > \frac{2}{3}x+3$ ----> inequality A

The solution of the inequality A is the shaded area above the dashed line $y=\frac{2}{3}x+3$

The slope of the dashed line is positive

The y-intercept of the dashed line A is (0,3)

The x-intercept of the dashed line A is (-4.5,0)

$y\leq -\frac{1}{3}x+2$ ----> inequality B

The solution of the inequality B is the shaded area below the solid line $y=-\frac{1}{3}x+2$

The slope of the solid line is negative

The y-intercept of the solid line B is (0,2)

The x-intercept of the solid line B is (6,0)

The solution of the system of inequalities is the shaded area between the shaded line and the solid line

using a graphing tool

see the attached figure

3 0

2 years ago

Read 2 more answers

Which of the following functions gives the radius, r(v), of a conical artifact that is 20 inches tall as a function of its volum

irinina [24]

<h3>Radius as function of volume is:</h3>

$r(v) = \sqrt{\frac{3v}{20 \pi }}\ inches$

Solution:

The volume of cone is given as:

$v = \frac{1}{3}\pi r^{2} h$

Where,

r is the radius

h is the height

From given,

height = 20 inches

From formula,

$v = \frac{1}{3}\pi r^{2} h$

Rearrange , so that r is alone in left side of equation

$3v = \pi r^2 h\\\\\pi r^2 h = 3v\\\\r^2 = \frac{3v}{\pi h}\\\\Take\ square\ root\ on\ both\ sides\\\\r = \sqrt{\frac{3v}{\pi h}}$

Substitute h = 20

$r = \sqrt{\frac{3v}{20 \pi }}$

Thus, radius as function of volume is:

$r(v) = \sqrt{\frac{3v}{20 \pi }}\ inches$

4 0

2 years ago

1. The following are the number of hours that 10 police officers have spent being trained in how to handle encounters with peopl

dusya [7]

Answer:

$Range = 16$

$Inter\ Quartile\ Range = 6.75$

$Variance = 20.44$

$Standard\ Deviation = 4.52$

Step-by-step explanation:

Given

4, 17, 12, 9, 6, 10, 1, 5, 9, 3

Calculating the range;

$Range = Highest - Lowest$

From the given data;

Highest = 17 and Lowest = 1

Hence;

$Range = 17 - 1$

$Range = 16$

Calculating the Inter-quartile Range

Inter quartile range (IQR) is calculates as thus

$IQR = Q_3 - Q_1$

Where

Q3 = Upper Quartile and Q1 = Lower Quartile

Start by arranging the data in ascending order

1, 3, 4, 5, 6, 9, 9, 10, 12, 17

N = Number of data; N = 10

---------------------------------------------------------------------------------

Calculating Q3

$Q_3 = \frac{3}{4}(N+1) th\ item$

Substitute 10 for N

$Q_3 = \frac{3}{4}(10+1) th\ item$

$Q_3 = \frac{3}{4}(11) th\ item$

$Q_3 = \frac{33}{4} th\ item$

$Q_3 = 8.25 th\ item$

Express 8.25 as 8 + 0.25

$Q_3 = (8 + 0.25) th\ item$

$Q_3 = 8th\ item + 0.25 th\ item$

Express 0.25 as fraction

$Q_3 = 8th\ item +\frac{1}{4} th\ item$

$Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)$

From the arranged data;

$8th\ item = 10$ and $9th\ item = 12$

$Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)$

$Q_3 = 10 +\frac{1}{4} (12 - 10)$

$Q_3 = 10 +\frac{1}{4} (2)$

$Q_3 = 10 +0.5$

$Q_3 = 10.5$

Calculating Q1

$Q_1 = \frac{1}{4}(N+1) th\ item$

Substitute 10 for N

$Q_1 = \frac{1}{4}(10+1) th\ item$

$Q_1 = \frac{1}{4}(11) th\ item$

$Q_1 = \frac{11}{4} th\ item$

$Q_1 = 2.75 th\ item$

Express 2.75 as 2 + 0.75

$Q_1 = (2 + 0.75) th\ item$

$Q_1 = 2nd\ item + 0.75 th\ item$

Express 0.75 as fraction

$Q_1 = 2nd\ item +\frac{3}{4} th\ item$

$Q_1 = 2nd\ item +\frac{3}{4} (3rd\ item - 2nd\ item)$

From the arranged data;

$2nd\ item = 3$ and $3rd\ item = 4$

$Q_1 = 3 +\frac{3}{4} (4 - 3)$

$Q_1 = 3 +\frac{3}{4} (1)$

$Q_1 = 3 +0.75$

$Q_1 = 3 .75$

---------------------------------------------------------------------------------

Recall that

$IQR = Q_3 - Q_1$

$IQR = 10.5 - 3.75$

$IQR = 6.75$

Calculating Variance

Start by calculating the mean

$Mean = \frac{1+3+4+5+6+9+9+10+12+17}{10}$

$Mean = \frac{76}{10}$

$Mean = 7.6$

Subtract the mean from each data, then square the result

$(1 - 7.6)^2 = (-6.6)^2 = 43.56$

$(3 - 7.6)^2 = (-4.6)^2 = 21.16$

$(4 - 7.6)^2 = (-3.6)^2 = 12.96$

$(5 - 7.6)^2 = (-2.6)^2 = 6.76$

$(6 - 7.6)^2 = (-1.6)^2 = 2.56$

$(9 - 7.6)^2 = (1.4)^2 = 1.96$

$(10 - 7.6)^2 = (2.4)^2 = 5.76$

$(12 - 7.6)^2 = (4.4)^2 = 19.36$

$(17 - 7.6)^2 = (9.4)^2 = 88.36$

Sum the result

$43.56 + 21.16 + 12.96 + 6.76 + 2.56 + 1.96 + 1.96 + 5.76 + 19.36 + 88.36 = 204.4$

Divide by number of observation;

$Variance = \frac{204.4}{10}$

$Variance = 20.44$

Calculating Standard Deviation (SD)

$SD = \sqrt{Variance}$

$SD = \sqrt{20.44}$

$SD = 4.52$ (Approximated)

4 0

2 years ago

June has a credit card balance of $4,350 that comes with a 19% APR. She would like to have the balance paid off in the next 8 mo

omeli [17]

It's B on E2020, I just took the test.

3 0

2 years ago

Read 2 more answers