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katrin [286]
2 years ago
6

Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square. Isolate the constant b

y both sides of the equation. Add to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced. Write the trinomial x2 – 6x + 9 as squared. Use the square root property of equality to get x – 3 = ± . Isolate the variable to get solutions of –1 and 7.
ANSWERS:
Adding 7 to
9
x-3
4
Mathematics
2 answers:
Oksi-84 [34.3K]2 years ago
8 0

Answer:

1 adding 7 to

2 9

3 x-3

4 4

Step-by-step explanation:

Vera_Pavlovna [14]2 years ago
4 0

Answers: Using the process of completing the square:

1. Isolate the constant by <u>adding 7 to</u> both sides of the equation:

x^2-6x-7+7=0+7

x^2-6x=7

2. Add <u>9</u> to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced:

x^2-6x+9=7+9

x^2-6x+9=16

3. Write the trinomial x2 – 6x + 9 as squared:

<u>(x-3)^2</u> = 16

4. Use the square root property of equality to get x – 3 = ±<u>4</u> .

sqrt[ (x-3)^2 ] = ± sqrt(16)

x-3 = ±4

5. Isolate the variable to get solutions of –1 and 7.

x-3 = ±4

x-3+3 = ±4+3

x = ±4+3

x1=-4+3→x1=-1

x2=+4+3→x2=7

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Answer:

P (Z

Step-by-step explanation:

We want the probability that the 35 cars are loaded onto the ferry. Therefore:

Since  

μ=1.8  and  σ=0.5  we have:

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Since  

(x−μ)/σ=Z and  

(35-1.8)/0.5=66.4

we have:

P (X

Use the standard normal table to conclude that:

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2 years ago
Read 2 more answers
Sarah buys a new bike. The total cost of the bike including taxes is $349. She pays $100 down and then agrees to pay the balance
OlgaM077 [116]

The amount of each of the 6 payments will be $41.50

Step-by-step explanation:

Given,

Cost of bike including taxes = $349

Down payment = $100

Amount left to pay = Cost of bike - Down payment

Amount left to pay = 349 - 100

Amount left to pay = $249

She agrees to pay in 6 equal payments, therefore, we will divide the total amount to pay by 6.

Amount to pay for one month = \frac{Amount\ left\ to\ pay}{No.\ of\ months}

Amount to pay for one month = \frac{249}{6} = \$41.50

The amount of each of the 6 payments will be $41.50

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/10940255
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#LearnwithBrainly

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Solve x2 + 10x + 12 = 36 for x.
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Before the distribution of certain statistical software, every fourth compact disk (CD) is tested for accuracy. The testing proc
lilavasa [31]

Answer:

a) For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

P(R) =\frac{1}{4} =0.25

The failure probability for each program are given by:

P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932

So then the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

And if we use the fact that we have 4 possible test the true probability of interest would be:

P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017

b) p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))

And replacing we got:

p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484

c) From part a we now that the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

So then if we have 100 CDs the expected number of rejected Cd's are:

100*0.068= 6.8 \approx 7

Step-by-step explanation:

Part a

For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

P(R) =\frac{1}{4} =0.25

The failure probability for each program are given by:

P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932

So then the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

And if we use the fact that we have 4 possible test the true probability of interest would be:

P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017

Part b

For this case we want the probability that it failed program 2 or 3

So then we can find this probability like this:

p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))

And replacing we got:

p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484

Part c

From part a we now that the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

So then if we have 100 CDs the expected number of rejected Cd's are:

100*0.068= 6.8 \approx 7

3 0
2 years ago
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