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kotegsom [21]
2 years ago
5

f(x) = 7x g(x) = 7x + 6 Which statement about f(x) and its translation, g(x), is true? The domain of g(x) is {x | x > 6}, and

the domain of f(x) is {x | x > 0}. The domain of g(x) is {y | y > 0}, and the domain of f(x) is {y | y > 6}. The asymptote of g(x) is the asymptote of f(x) shifted six units down. The asymptote of g(x) is the asymptote of f(x) shifted six units up.
Mathematics
2 answers:
Cloud [144]2 years ago
7 0
The asymptote of g(x) is the aymptote of f(x) shifted six units up
Oksanka [162]2 years ago
5 0

Answer:

The correct option is 4. The asymptote of g(x) is the asymptote of f(x) shifted six units up.

Step-by-step explanation:

The given functions are

f(x)=7x

g(x)=7x+6

Both are linear function and the domain of a linear function is all real real numbers.

Domain of f(x) = {x | x∈R }

Domain of g(x) = {x | x∈R }

Therefore option 1 and 2 are incorrect.

The linear asymptote of a linear function f(x)=mx+b is

y=mx+b+\delta x

Where, δx is infinitely small number, but not quite equal to 0.

The asymptote of f(x) is

y=7x+\delta x

The asymptote of g(x) is

y=7x+6+\delta x

It means the asymptote of f(x) shifts six units up to get the asymptote of g(x).

Therefore option 4 is correct. The asymptote of g(x) is the asymptote of f(x) shifted six units up.

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A student spent 2 hours studying, 1 hour doing laundry, and 1 ½ hours watching television. What percentage of time was spent doi
ivanzaharov [21]
Total hours working = 4.5 hrs 
hours doing laundry = 1 hr 

Percentage of time doing laundry = 1/4.5 
Percentage of time doing laundry = 22.22%

5 0
2 years ago
Read 2 more answers
Evaluate the expression. P(9, 3) · P(5, 4)
boyakko [2]

Answer:

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

Step-by-step explanation:

For this problem we want to find the following expressionÑ

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

6 0
2 years ago
A 12-centimeter rod is held between a flashlight and a wall as shown. Find the length of the shadow on
choli [55]

Answer:

48 cm

Step-by-step explanation:

Given:

Distance of rod from the wall = 45 cm

Distance of rod from the light = 15 cm

Length of rod = 12 cm

We can see that <DAM and <BAF are equal

Also, <DMA and <BFM are equal because they are corresponding angles

To find the length of the shadow, let's take the equation

\frac{DM}{BF} = \frac{AM}{A.F}

Where.:

DM = ½ of length of the rod = ½*12 = 6

A.F = 15 + 45 = 60 cm

AM = 15 cm

Therefore,

\frac{DM}{BF} = \frac{AM}{A.F}

= \frac{6}{BF} = \frac{15}{60}

Cross multiplying, we have:

15 * B.F = 60 * 6

15 * B.F = 360

BF = \frac{360}{15}

BF = 24 cm

The shadow on the wall =

2 * BF

= 2 * 24

= 48 cm

The shadow on the wall is 48 cm

7 0
1 year ago
Josh has $500 in his savings account. He deposits $25 into his savings account each month. He purchased home theater equipment f
zzz [600]

Answer:

  B. 10 months

Step-by-step explanation:

The balance on the loan will be ...

  b = 1600 - 80t . . . . . . where t is the number of months of payments

The balance in the savings account will be ...

  s = 500 + 25t

The savings account balance will be at least as much as the loan balance when ...

  s ≥ b

  500 +25t ≥ 1600 -80t . . . substitute the account balance expressions

  105t ≥ 1100 . . . . . . . . . . . . add 80t -500

  t ≥ 1100/105 ≈ 10.48 ≈ 10

It will take Josh 10 months to have enough savings to pay the loan in full.

_____

<em>Comment on rounding</em>

IMO, it makes no sense to round down, as Josh will NOT have enough in 10 months. He will have enough after he makes one more payment of $80. At 10 months, the loan balance is $50 more than the savings balance. It will be 11 months before there is enough savings to pay off the loan.

4 0
2 years ago
. The mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days. Suppose that the incubation ti
Paul [167]

Answer:

Step-by-step explanation:

Given that the  mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days.

Let X be the incubation time for a type of fertilized egg kept at a certain temperature is 25 days.

X is N(25, 1)

a) Normal curve is in the attached file

b) the probability that a randomly selected fertilized egg hatches in less than 23 days

=P(X

we convert x into Z score and use std normal distn table to find probability

P(X

i.e. we can say only 2.5% proportion will hatch in less than 23 days.

8 0
2 years ago
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