Remember that an extraneous solution of an equation is a solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation.
First, we are going to solve our equation algebraically:
Step 1 simplify the equation:
Step 2 subtract 5 from both sides of the equation:
Step 3 square both sides of the equation:
Next, we are going to replace our solution in our original equation and check if it is a valid solution:
Since 9 is not equal to 1, is not valid solution of the equation; therefor it is an extraneous solution.
We can conclude that the correct answer is: x = 16, solution is extraneous
Adiya’s method is not correct. To form a perfect square trinomial, the constant must be isolated on one side of the equation. Also, the coefficient of the term with an exponent of 1 on the variable is used to find the constant in the perfect square trinomial. Adiya should first get the 20x term on the same side of the equation as x2. Then she would divide 20 by 2, square it, and add 100 to both sides.
Answer:
The cost is $9.70 per kilogram.
Step-by-step explanation:
This can be solved by a rule of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.
Solution:
The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:
1 pound - xkg
2.2 pound - 1 kg
kg
Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?
$4.40 - 0.45kg
$x - 1kg
The cost is $9.70 per kilogram.
Aaa^3bxa^2b^3abx^4
=aaa^3a^2abb^3bxx^4
=a^(1+1+3+2+1)b^(1+3+1)x^(1+4)
=a^8^b^5x^5
Complete Question
Each summer Primo Pizza and Pizza Supreme compete to see who has the larger summer profit.
Let p(x) represent Primo Pizza's profit (in dollars) x days after June 1. Let s(x) represent Pizza Supreme's profit (in dollars) x days after June 1.
Suppose Primo Pizza's profit each day is 1.9 times as large as the profit of Pizza Supreme.
Write a function formula for p using the function s
Answer:
The function formula for p using the function s is p(x) = 1.9s(x)
Step-by-step explanation:
Given
p(x) = Primo Pizza's profit (in dollars) x days after June 1.
s(x) = Pizza Supreme's profit (in dollars) x days after June 1.
It is given that Primo Pizza's profit each day is 1.9 times as large as the profit of Pizza Supreme.
This implies that
p(x) = 1.9*s(x)
So, p(x) = 1.9s(x)
Hence, the function formula for p using the function s is p(x) = 1.9s(x)
