We know that
Half-life is modeled by the formula
An=A0*(0.5)<span>^[t/h)]
where
An----------> </span>is the amount remaining after a time t
A0----------> is the initial quantity
t------------> is the time
h------------> is the half-life of the decaying quantity
in this problem
h=1601 years
A0=50 g
An=?
t=100 years
An=A0*(0.5)^[t/h)]---------> An=50*(0.5)^[100/1601)]-----> 47.88 gr
the answer is 47.88 g
Answer:

Step-by-step explanation:
we know that
The absolute value function has two solutions
Observing the graph
the solutions are
and 
First solution (case positive)
assume the symbol of the first solution and then compare the results




Second solution (case negative)

Multiply by -1 both sides

substitute the value of b and compare the results


-------> is correct
The answers are (-3, -4) and (-5, -4).
The lines y=x+2 and y=x are parallel, because they have the same slope.
Quadratic equation: ax² + bx + c =0
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6
x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31