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2 years ago

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During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim

ental probability of rolling a two was approximately 1/9. Why is Juan’s experimental probability incorrect?

2 answers:

lana [24]2 years ago

7 0

Answer:

Juan's claim is incorrect. The correct experimental probablilty is StartFraction 2 over 9 EndFraction.

Step-by-step explanation:

took the test.

natita [175]2 years ago

3 0

Answer:

$\frac{2}{9}$

Step-by-step explanation:

Given :

Juan rolled a six-sided number cube 18 times.

The number two occurred four times.

To Find: Juan claimed the experimental probability of rolling a two was approximately 1/9. Why is Juan’s experimental probability incorrect?

Solution:

Total events = number of times cube rolled = 18

Favorable events = The number two occurred four times. = 4

So, Experimental probability = $\frac{\text{Favorable events}}{\text{Total events}}$

= $\frac{4}{18}$

= $\frac{2}{9}$

Thus the experimental probability of rolling a two was $\frac{2}{9}$

So, Juan’s experimental probability was incorrect.

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is $\overline A=\textrm{Missing a target at least once}$

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, $P(A)=0.95^{10}=0.5987$

We know that the sum of probability of an event and its complement is 1.

So, $P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%$

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

6 0

1 year ago

Read 2 more answers

A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th

Kitty [74]

Answer:

a

The 90% confidence interval is $52561.13 < \mu < 57540.8$

b

Confidence interval for the population men between <u>$52561.13</u> up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

The sample size is $n = 25$

The sample mean is $\= x = \$ 55,051$

The standard deviation is $\sigma = \$ 7,568$

Given that the confidence level is 90% then the level of confidence is mathematically represented as

$\alpha = 100 -90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table the values is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }$

$E = 2489.9$

The 90% confidence interval is mathematically evaluated as

$\= x -E < \mu < \= x +E$

substituting values

$55051 - 2489.8 < \mu < 55051 + 2489.8$

$52561.13 < \mu < 57540.8$

6 0

2 years ago

a teapot is 1/3 full of tea. When all of the tea is poured into an empty container, the container is 2/3 full. what fraction of

motikmotik

(1/3)t = (2/3)c, where "t" is for teapot and "c" is for the container.
Multiply both sides by (3/2) in order to get 1 on the right-hand side.
(3/2)(1/3)t = (3/2)(2/3)C
simplify the equation to get the answer which is:
(1/2) teacup = 1 full container.
Hope this helps :)

4 0

1 year ago

Marcus and Jeremy both evaluated the expression −52 + 3. Marcus said the answer was −22. Jeremy said the answer was 28. Who is c

Artyom0805 [142]

Answer:

Alright, the answer to the equation -52+3= -49

Step-by-step explanation:

I don't know how the heck Marcus and Jeremy got -22 and 28 but both are wrong. If there were a picture so I could see their work, I would be able to figure it out.

Anyways, The math is:

-52 + 3 which is pretty much 52-3 and then the answer has a negative sign.

-52 goes up 3 because technically the negative sign is down. Counting up 3 from 52 equals -49.

6 0

1 year ago

Read 2 more answers

A baker uses 13 1/2 cups of flour to make bread. She uses 2 1/4 cups of flour to make each loaf. The baker sells 2/3 of the loav

ollegr [7]

Answer:

She sells 4 loaves of bread

Step-by-step explanation:

Lets explain how to solve the problem

→ A baker uses $13\frac{1}{2}$ cups of flour to make bread

→ She uses $2\frac{1}{4}$ cups of flour to make each loaf

From these information we can find the number of loaves of bread

she can make

∵ There are $13\frac{1}{2}$ cups of flour

∵ Each loaf of bread needs $2\frac{1}{4}$ cups of flour

∴ The number of loaves = $13\frac{1}{2}$ ÷ $2\frac{1}{4}$

To divide two mixed numbers make them improper fractions and

change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∵ $13\frac{1}{2}$ = $\frac{(13)(2)+1}{2}$

∴ $13\frac{1}{2}$ = $\frac{27}{2}$

∵ $2\frac{1}{4}$ = $\frac{(2)(4)+1}{4}$

∴ $2\frac{1}{4}$ = $\frac{9}{4}$

∴ The number of loaves = $\frac{27}{2}$ × $\frac{4}{9}$

∴ The number of loaves = 6

<em>She can make 6 loaves</em>

→ The baker sells $\frac{2}{3}$ of the loaves of bread that she makes

→ We need to find the number of loves of bread she sells

∵ She sells $\frac{2}{3}$ of the loaves

∵ There are 6 loves

∴ The number of loaves she sells = 6 × $\frac{2}{3}$ = 4

<em>She sells 4 loaves of bread</em>

7 0

1 year ago