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Nonamiya [84]
2 years ago
7

During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim

ental probability of rolling a two was approximately 1/9. Why is Juan’s experimental probability incorrect?
Mathematics
2 answers:
lana [24]2 years ago
7 0

Answer:

Juan's claim is incorrect. The correct experimental probablilty is StartFraction 2 over 9 EndFraction.

Step-by-step explanation:

took the test.

natita [175]2 years ago
3 0

Answer:

\frac{2}{9}

Step-by-step explanation:

Given :

Juan rolled a six-sided number cube 18 times.

The number two occurred four times.

To Find: Juan claimed the experimental probability of rolling a two was approximately 1/9. Why is Juan’s experimental probability incorrect?

Solution:

Total events = number of times cube rolled = 18

Favorable events = The number two occurred four times.  = 4

So, Experimental probability = \frac{\text{Favorable events}}{\text{Total events}}

                                               = \frac{4}{18}

                                               = \frac{2}{9}

Thus the experimental probability of rolling a two was  \frac{2}{9}

So, Juan’s experimental probability was incorrect.

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An electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are l
Tju [1.3M]

Answer:

Step-by-step explanation:

given that an  electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are labeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each

Sample space for selecting one resistor from first box

= {9, 10, 11, 12, 13}

A = {11,12,13} (because >10)

Sample space for selecting one resistor from second  box

={18,19,20,21,22}

B={18}

Sample space for sum would be

{27, 28, 29, 30, 31, 32, 33, 34, 35}

C = {(9,19) , (10,18)}

8 0
2 years ago
Which graph shows a dilation? On a coordinate plane, 2 quadrilaterals are shown. The larger quadrilateral has points (negative 4
gayaneshka [121]

Answer:

On a coordinate plane, 2 quadrilaterals are shown. The larger quadrilateral has points (negative 5, 3), (1, 3), (4, 0), (negative 2, 0). The smaller quadrilateral has points (negative 1, 0), (negative 2, 1), (0, 1), and (1, 0).      

Step-by-step explanation:

<u>Larger quadrilateral</u>

Length of the top and bottom segments are 6 units.

Length of the left and right sides:

d = √[(-5 - (-2))² + (3 - 0)²] = √[3² + 3²] = √(2*3²) = 3√2 units

From point (-5, 3) to point (-2, 0) the slope is:

m = (3 - 0)/(-5 - (-2)) = -1

<u>Smaller quadrilateral</u>

Length of the top and bottom segments are 2 units.

Length of the left and right sides:

d = √[(-2 - (-1))² + (1 - 0)²] = √[1² + 1²] = √2 units

From point (-2, 1) to point (-1, 0) the slope is:

m = (1 - 0)/(-2 - (-1)) = -1

If you dilate the smaller quadrilateral by a factor of 3, you get the larger quadrilateral (they have the same slope, and 3 times length of the smaller quadrilateral is equal to the length of the larger quadrilateral).

5 0
2 years ago
Read 2 more answers
You work at a fruit market. Bananas cost 50¢ a pound. A customer hands you a bunch of bananas that weighs 3 pounds. How much sho
weqwewe [10]
3 pounds of bananas cost $1.50
5 0
2 years ago
Read 2 more answers
The radius of a circular pond is increasing at a constant rate, which can be modeled by the function , where t is time in months
horrorfan [7]

Answer:

B. A(r(t)) = 25πt²

Step-by-step explanation:

Find the completed question below

The radius of a circular pond is increasing at a constant rate, which can be modeled by the function r(t) = 5t where t is time in months. The area of the pond is modeled by the function A(r) = πr². The area of the pond with respect to time can be modeled by the composition . Which function represents the area with respect to time? A. B. C. D.

Given

A(t) = πr²

r(t) = 5t

We are to evaluate the composite expression A(r(t))

A(r(t)) = A(5t)

To get A(5t), we will replace r in A(t) with 5t and simplify as shown

A(5t) = π(5t)²

A(5t) = π(25t²)

A(5t) = 25πt²

A(r(t)) = 25πt²

Hence the composite expression A(r(t)) is 25πt²

Option B is correct.

5 0
2 years ago
A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids
NemiM [27]

Answer:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35

Now we can find the sampel deviation with this formula:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

6 0
2 years ago
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