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emmasim [6.3K]
2 years ago
13

Factor the polynomial 12c9 + 28c7. Find the GCF of 12c9 and 28c7. 4c7 Write each term as a product, where one factor is the GCF.

4c7(3c2) + 4c7(7) Use the distributive property. What is the resulting expression? 4(3c9 + 7c7) 4c7(3c2 + 7) 4c7(3c9 + 7c7) 4c7(12c9 + 28c7)
Mathematics
2 answers:
BabaBlast [244]2 years ago
7 0

Answer:

its b.......

Step-by-step explanation:

saul85 [17]2 years ago
6 0
We are asked in the problem to determine the factored form of a polynomial given the expression 12c9 + 28c7 by finding the GCF. GCF or the greatest common factor is the greatest number (including variable if applicable) that is divisible to the terms included in the polynomial. In this case, the GCF of 12 and 28 is 4 while the GCF of c9 and c7 is c7. We multiply both GCFs from the variable and numerical side.
Hence the complete GCF is 4c7. In this case, the factored form of the polynomial using the GCF is 4c7 ( 3c2 + 7). The answer to this problem is B. 
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Answer is attached.

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George tells you that when variables are in the denominator, the equation four over five plus three over x equals one over two b
jeka57 [31]
<span><span><u>Answer</u>
This explanation shows that the equation is solvable and there is not where in the steps we get a zero on the denominator.


</span><span><u>Explanation</u>
</span><span>The equation given in the statement is;
4/5+3/x=1/2
This equation can be solved as follows:
4/5+3/x=1/2
3/x=1/2-4/5=(5-8)/10
3/x= -3/10
Taking the reciprocal on both side of the equation;
x/3=-10/3
Multiplying by 3 both sides we get;
</span><span>x= -10
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2 years ago
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a model car is one tenth of the size of the real car the models measures 42cm longs what the length of length of the real car
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Just multiply 42 by 10 and that gives you 420 , so the real car has a length of 420cm or 4.2 metres :)
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Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 888 wings for \$7$7dollar
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Learning Task 3. Find the equation of the line. Do it in your notebook.
Wewaii [24]

Answer:

1) The equation of the line in slope-intercept form is y = 5\cdot x +9. The equation of the line in standard form is -5\cdot x + y = 9.

2) The equation of the line in slope-intercept form is y = \frac{2}{5}\cdot x +\frac{14}{5}. The equation of the line in standard form is -2\cdot x +5\cdot y = 14.

3) The equation of the line in slope-intercept form is y = 3\cdot x +4. The equation of the line in standard form is -3\cdot x +y = 4.

4) The equation of the line in slope-intercept form is y = 2\cdot x + 6. The equation of the line in standard form is -2\cdot x +y = 6.

5) The equation of the line in slope-intercept form is y = \frac{5}{6}\cdot x -\frac{7}{6}. The equation of the line in standard from is -5\cdot x + 6\cdot y = -7.

Step-by-step explanation:

1) We begin with the slope-intercept form and substitute all known values and calculate the y-intercept: (m = 5, x = -1, y = 4)

4 = (5)\cdot (-1)+b

4 = -5 +b

b = 9

The equation of the line in slope-intercept form is y = 5\cdot x +9.

Then, we obtain the standard form by algebraic handling:

-5\cdot x + y = 9

The equation of the line in standard form is -5\cdot x + y = 9.

2) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = 3, y_{1} = 4, x_{2} = -2, y_{2} = 2)

3\cdot m + b = 4 (Eq. 1)

-2\cdot m + b = 2 (Eq. 2)

From (Eq. 1), we find that:

b = 4-3\cdot m

And by substituting on (Eq. 2), we conclude that slope of the equation of the line is:

-2\cdot m +4-3\cdot m = 2

-5\cdot m = -2

m = \frac{2}{5}

And from (Eq. 1) we find that the y-Intercept is:

b=4-3\cdot \left(\frac{2}{5} \right)

b = 4-\frac{6}{5}

b = \frac{14}{5}

The equation of the line in slope-intercept form is y = \frac{2}{5}\cdot x +\frac{14}{5}.

Then, we obtain the standard form by algebraic handling:

-\frac{2}{5}\cdot x +y = \frac{14}{5}

-2\cdot x +5\cdot y = 14

The equation of the line in standard form is -2\cdot x +5\cdot y = 14.

3) By using the slope-intercept form, we obtain the equation of the line by direct substitution: (m = 3, b = 4)

y = 3\cdot x +4

The equation of the line in slope-intercept form is y = 3\cdot x +4.

Then, we obtain the standard form by algebraic handling:

-3\cdot x +y = 4

The equation of the line in standard form is -3\cdot x +y = 4.

4) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = -3, y_{1} = 0, x_{2} = 0, y_{2} = 6)

-3\cdot m + b = 0 (Eq. 3)

b = 6 (Eq. 4)

By applying (Eq. 4) on (Eq. 3), we find that the slope of the equation of the line is:

-3\cdot m+6 = 0

3\cdot m = 6

m = 2

The equation of the line in slope-intercept form is y = 2\cdot x + 6.

Then, we obtain the standard form by algebraic handling:

-2\cdot x +y = 6

The equation of the line in standard form is -2\cdot x +y = 6.

5) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = -1, y_{1} = -2, x_{2} = 5, y_{2} = 3)

-m+b = -2 (Eq. 5)

5\cdot m +b = 3 (Eq. 6)

From (Eq. 5), we find that:

b = -2+m

And by substituting on (Eq. 6), we conclude that slope of the equation of the line is:

5\cdot m -2+m = 3

6\cdot m = 5

m = \frac{5}{6}

And from (Eq. 5) we find that the y-Intercept is:

b = -2+\frac{5}{6}

b = -\frac{7}{6}

The equation of the line in slope-intercept form is y = \frac{5}{6}\cdot x -\frac{7}{6}.

Then, we obtain the standard form by algebraic handling:

-\frac{5}{6}\cdot x +y =-\frac{7}{6}

-5\cdot x + 6\cdot y = -7

The equation of the line in standard from is -5\cdot x + 6\cdot y = -7.

6 0
1 year ago
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