Solution:
In the game Singularity, broken objects can be restored to their original condition by reversing time. This is an example of which time element of player adjustment.
Thus the required answer is player adjusted.
Software as a Service cloud model is ideal for Rita’s business. SaaS are office solutions that allow Rita’s small business to work more efficiently and in a more organized way. Most SaaS applications are used for invoicing and accounting, sales, performance monitoring, and overall planning. SaaS applications can save Rita money. They do not require the deployment of a large infrastructure at her location. As a result, it drastically reduces the upfront commitment of resources. Whoever manages SaaS’s IT infrastructure running the applications brings down fees for software and hardware maintenance. SaaS has generally been acknowledged to be safer than most on-premise software.
Email client as port 25 is the default port for an email server.
Answer:
#include <iostream>
#include <cstdlib>
using namespace std;
char grade(double marks){
if(marks>=90)
{
return 'A';
}
else if (marks >=80 && marks<90)
{
return 'B';
}
else if (marks >=70 && marks<80)
{
return 'C';
}
else if (marks >=60 && marks<70)
{
return 'D';
}
else if ( marks<60)
{
return 'F';
}
}
int main()
{
double marks;
cout <<"Ener marks";
cin >>marks;
char grd=grade(marks);
cout<<"Grae is "<<grd;
return 0;
}
Explanation:
Take input from user for grades in double type variable. Write function grade that takes a parameter of type double as input. Inside grade function write if statements defining ranges for the grades. Which if statement s true for given marks it returns grade value.
In main declare a variable grd and store function returned value in it.
Answer:
#include<iostream>
using namespace std;
void main()
{
int townA_pop,townB_pop,count_years=1;
double rateA,rateB;
cout<<"please enter the population of town A"<<endl;
cin>>townA_pop;
cout<<"please enter the population of town B"<<endl;
cin>>townB_pop;
cout<<"please enter the grothw rate of town A"<<endl;
cin>>rateA;
cout<<"please enter the grothw rate of town B"<<endl;
cin>>rateB;
while(townA_pop < townB_pop)//IF town A pop is equal or greater than town B it will break
{
townA_pop = townA_pop +( townA_pop * (rateA /100) );
townB_pop = townB_pop +( townB_pop * (rateB /100) );
count_years++;
}
cout<<"after "<<count_years<<" of years the pop of town A will be graeter than or equal To the pop of town B"<<endl;
}
Explanation:
