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Yuliya22 [10]
2 years ago
4

3 gallons of paint are used tonpaint 16 wooden signs.how much paint did each sign use. Between what two whole numbers does the a

nswer lie?
Mathematics
1 answer:
brilliants [131]2 years ago
5 0
Let us first relate to the situation: 3 gallons of paint are used to paint 16 wooden signs.
Thus,we need to  solve how much paint did each sign use
 Second question: between what two whole numbers does the answer lie?
=> 3 gallons of paints : 16 wooden sign.
=> 3 gallons / 16 wooden signs = 0.19 gallons of paint per wooden sign.
Therefore, every 1 wooden sign we will be suing 0.19 gallons of paint. 
Between which 2 whole number the answer lie, well, i can;t really tell since I 'm not sure what you mean.<span>
</span>
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g100num [7]

Answer:

The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

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   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

     \theta_B  =  32^o

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      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

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      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

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Use this to solve 3

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