A). because the roots are shown. The roots of this quadratic function would be x=2, and x=-2

x represents how many are sold. then multiply 80×3

then add your x together

then you must divide your x by 3440

8 is how many higher-priced speakers take you 8 and multiple it by 3 to get how many lower-priced speakers

you have 24 low priced speaker and 8 high priced speakers.
In this item, we let x be the number of corns and Y represent soybeans. The sum of these variables is 400. This is represented by the equation,
x + y = 400
The amount that needs to be earn by Tony is then represented by,
200x + 300y ≥ $60,000
Answer:
The median is
Step-by-step explanation:
From the question we are told that
The sample size is n = 100
The
measurements is 
Generally since that after 0.900 we have 0.901 , then the

in the same manner the
,
Given that 0.902 was observed three times it means that
,
Given that 0.903 was observed two times it means that
,
Given that 0.903 was observed four times it means that
,
Given that the highest measurement is 0.958 then then the 
Generally the median is is mathematically represented as
![Median = \frac{ [\frac{n^{th}}{2}] + [(\frac{n}{2})^{th} + 1 ]}{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%20%5B%5Cfrac%7Bn%5E%7Bth%7D%7D%7B2%7D%5D%20%20%2B%20%5B%28%5Cfrac%7Bn%7D%7B2%7D%29%5E%7Bth%7D%20%2B%201%20%5D%7D%7B2%7D)
=> ![Median = \frac{ [\frac{100^{th}}{2}] + [(\frac{100}{2})^{th} + 1 ]}{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%20%5B%5Cfrac%7B100%5E%7Bth%7D%7D%7B2%7D%5D%20%20%2B%20%5B%28%5Cfrac%7B100%7D%7B2%7D%29%5E%7Bth%7D%20%2B%201%20%5D%7D%7B2%7D)
=> ![Median = \frac{ [50^{th}] + [51^{th} ]}{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%20%5B50%5E%7Bth%7D%5D%20%20%2B%20%5B51%5E%7Bth%7D%20%5D%7D%7B2%7D)
=>
=>
Answer:
The distance at which the timekeeper is the race car at the start is 50 feet.
Step-by-step explanation:
You know that the car's distance from the timekeeper is represented by
y=293*x +50
where x is time in seconds and y is distance in feet from the timekeeper's position.
You want to determine how far the timekeeper is from the race car at the start. That is, the distance the timekeeper is from the car when the time is equal to zero. This indicates that x = 0. Replacing x by that value in the expression of the distance of the car from the timekeeper as a function of time and solving:
y=293*0 +50
you get:
y=50
<u><em>The distance at which the timekeeper is the race car at the start is 50 feet.</em></u>