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omeli [17]
2 years ago
11

Heather has a bag containing 4 marbles: 1 red, 1 blue, and 2 green. She draws 1 marble out of the bag, replaces it, and then dra

ws another marble. What is the denominator of the simplified fraction that represents P(red then blue then green)?
Mathematics
2 answers:
Alex_Xolod [135]2 years ago
7 0

1/4 for red

1/4 for blue

2/4 ( 1/2) for green

1/4 * 1/4 * 1/2 = 1/32

the denominator is the bottom number so it is 32

nexus9112 [7]2 years ago
4 0

Answer: \frac{1}{32}

Step-by-step explanation:

Given: Heather has a bag containing 4 marbles: 1 red, 1 blue, and 2 green.

She draws 1 marble out of the bag, replaces it, and then draws another marble, it means all the three events are independent.

Also we know that probability of any event = \frac{\text{favorable outcomes}}{\text{Total outcomes}}

therefore, the probability of drawing a red then blue then green marble is given by :-

\text{ P(red then blue then green)}=\frac{1}{4}\times\frac{1}{4}\times\frac{2}{4}\\\\\Rightarrow\ \text{ P(red then blue then green)}=\frac{1}{32}

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i = 2000 \times .02 \times 2
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2 years ago
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Use the normal approximation to the binomial distribution to answer this question. Fifteen percent of all students at a large un
Nataly_w [17]

Answer: 0.1289

Step-by-step explanation:

Given : The proportion of all students at a large university are absent on Mondays. : p=0.15

Sample size : n=12

Mean : \mu=np=12\times0.15=1.8

Standard deviation = \sigma=\sqrt{np(1-p)}

\Rightarrow\ \sigma=\sqrt{12(0.15)(1-0.15)}=1.23693168769\approx1.2369

Let x be a binomial variable.

Using the standard normal distribution table ,

P(x=4)=P(x\leq4)-P(x\leq3)              (1)

Z score fro normal distribution:-

z=\dfrac{x-\mu}{\sigma}

For x=4

z=\dfrac{4-1.8}{1.2369}\approx1.78

For x=3

z=\dfrac{3-1.8}{1.2369}\approx0.97

Then , from (1)

P(x=4)=P(z\leq1.78)-P(z\leq0.97)\\\\=0.962462-0.8339768\approx0.1289    

Hence, the probability that four students are absent = 0.1289

3 0
2 years ago
Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

So, remainder is 13 and -13.

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2 years ago
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What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

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Now ratio,

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Answer:

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Step-by-step explanation:

<u>Step 1</u>:-

Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.

by  Poisson random variable given that λ = 1.5 flaws/millimeter

Poisson distribution P(X= r) = \frac{e^{-\alpha } \alpha ^{r} }{r!}

<u>Step 2:</u>-

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