Answer:

So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:


So then P =11000 is the minimum that the least populated district could have.
Answer:
a = 5 and b = 12
Step-by-step explanation:
<u>Step 1: Find angle B</u>
<em>Angle C = 90°</em>
<em>Angle A = 22.6°</em>
<em>Angle B = B</em>
<em>All angles in a triangle are equal to 180°.</em>
Angle A + Angle B + Angle C = 180°
22.6 + 90 + B = 180°
B = 180 - 112.6
B = 67.4°
<u>Step 2: Find the value of side AC 'b'</u>
<em>Hypotenuse = 13</em>
<em>Adjacent = b</em>
<em>Angle A = 22.6°</em>
Cos (Angle) = Adjacent/Hypotenuse
Cos (22.6) = b/13
b = 12
<u>Step 3: Find the value of side CB 'a'</u>
<em>Hypotenuse = 13</em>
<em>Opposite = a</em>
<em>Angle A = 22.6°</em>
Sin (angle) = Opposite/Hypotenuse
Sin (22.6°) = a/13
a = 4.99 rounded off to 5
Therefore, the value of a=5 and b=12.
!!
Answer : 96
x – y = 16
--------> equation 1

x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation



Take common denominator to combine fractions


Add 8 on both sides

Multiply both sides by 
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.
Answer:
5.28°
Step-by-step explanation:
Draw the triangle formed by the sledding run. The hypotenuse is 300. The height is 27.6. The angle of depression is opposite of the height.
Using sine:
sin θ = 27.6 / 300
sin θ = 0.092
θ = 5.28°