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2 years ago

The four vertices of an inscribed quadrilateral divide a circle in the ratio 1 : 2 : 5 : 4.

Mathematics

2 answers:

Cerrena [4.2K]2 years ago

7 0

Answer:

for plato users the answers are 45,75,135,105

Step-by-step explanation:

pickupchik [31]2 years ago

4 0

Answer:

The four angles of the quadrilateral are 30°, 60°, 150°, and 120°, respectively.

Step-by-step explanation:

Given : The four vertices of an inscribed quadrilateral divide a circle in the ratio 1 : 2 : 5 : 4.

To find : The four angles of the quadrilateral are °, °, °, and °, respectively.

Solution : We have given that The four vertices of an inscribed quadrilateral divide a circle in the ratio 1 : 2 : 5 : 4.

Let the angle of the quadrilateral is x

Then all the angles are x , 2x , 5x ,4x

Complete angle formed by circle is 360 °

Sum of all the angle are 360

x + 2x + 5x + 4x = 360 .

12 x = 360 .

On dividing both sids by 12.

x = 30 .

Then

2x = 60

5x = 5 * 30 = 150 .

4x = 4 *30 = 120 .

Therefore, The four angles of the quadrilateral are 30°, 60°, 150°, and 120°, respectively.

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2.8 meters linen divided into 45 cm pieces = # of pieces and waste

pogonyaev

2.8 meter= 2800cms

To solve this, we can create a simple algebraic equation:
45x=2800
Divide both sides by 45.
(45x)/45=(2800)/45
x=62.222

You can make 62 full pieces.

To find the waste, multiply the numbers of pieces by the length of each.
62*45
=2790
2800-<span>2790
=10 centimeters

There would be 10 centimeters of wasted linen.

Hope this helps!
-Benjamin</span>

6 0

2 years ago

ernesto tiene que enviar 4 encomiendas que tienen una masa del total de ocho decimos de kg. ¿que fraccion de kg. tiene cada una

Ber [7]

⭐Solución de problemas: Cada encomiendo tiene un peso de 2 kilogramos. En fracción esto representa 1/4 de la masa total.

¿por qué? Usted tiene una masa total entre los 4 encomiendos de 8 kilogramos, por lo que en orden

para expresar el peso de cada uno de ellos, tenemos

la siguiente expresión: Masa total de encomiendas (kg)/Número de encomiendas (unidad)Sustituimos:

8 kg/4 s

2 kg por encomiendaOfertamos la fracción que representa cada una en el total:

kg por encomienda/total de kg

2/8 x 1/4

6 0

2 years ago

The owners of an amusement park selected a random sample of 200 days and recorded the number of park patrons with annual passes

allochka39001 [22]

<h2>Answer with explanation:</h2><h2></h2>

The x% confidence interval interval interprets that we are x% confident that the true population mean falls in it.

Given : The owners of an amusement park computed a 90% confidence interval for the number of patrons with annual passes who visit the park daily.

Then, the correct interpretation of 90% confidence interval of (35, 51) will be that owners of an amusement park are 90% confident that the true population mean of the number of patrons with annual passes who visit the park daily lies in it.

6 0

2 years ago

A classic counting problem is to determine the number of different ways that the letters of millennium can be arranged. Find tha

Eddi Din [679]

Answer:

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of letters of the word "millennium" = 10

Letters repeated:

m = 2 times

i = 2 times

l = 2 times

n = 2 times

2. The number of different ways that the letters of millennium can be arranged is:

We will use the n! or factorial formula, this way:

10!/2! * 2! * 2! * 2!

(10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(2 * 1) * (2 * 1) * (2 * 1) * (2 *1)

3'628,800/2*2*2*2 = 3'628,800/16 = 226,800

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

7 0

2 years ago

Bethany,Lauren,Amanda,and David all meet at Family reunion. They are comparing their ages. They have found that Laura is 13 year

bazaltina [42]

The second system of equations,

$\left \{ {{y=\frac{x^2}{2}+\frac{13}{2}x} \atop {y=x^2-27x+129}}$
is correct.

We know that Bethany's age is x. Since Laura is 13 years older, her age is x+13. The product of their ages is equal to twice Amanda's age, and Amanda's age is y. This gives us:
x(x+13) = 2y

Using the distributive property, we have
x²+13x=2y

Dividing everything by 2 (to isolate y), we have:
x²/2 + (13/2)x = y

If we take 20 years off of Bethany's age, it is now represented as x-20. Taking 20 years off of Laura's age would be (x+13-20) or x-7. The product of their ages now is equal to David's age; David is 11 years older than Amanda, so his age is y+11. This gives us:

(x-20)(x-7)=y+11

Multiplying the binomials we have:"
x*x - 7*x - 20*x - 20(-7) = y+11
x²-7x-20x--140=y+11
x²-27x+140=y+11

To isolate y, subtract 11 from both sides:
x²-27x+140-11 = y+11-11
x²-27x+129 = y

7 0

2 years ago