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Svetlanka [38]
2 years ago
11

The following table shows the number of hours some middle school students in two cities spend texting each week: City A 9 27 17

24 21 12 25 25 18 City B 6 20 26 15 23 25 14 14 11 Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (6 points) Part B: Are the box plots symmetric? Justify your answer. (4 points)

Mathematics
1 answer:
Anastasy [175]2 years ago
6 0
Five-number summaries are: lowest value, highest value, upper quartile (Q₃), median (Q₂) and lower quartile (Q₁)

The first step is to rearrange each data set in ascending order as shown in the first diagram

The median (Q₂) of each data set is located on the 5^{th} value. 

Once the median is located, we then have the set of data on the left and on the right of median where we are going to locate the Q₁ and Q₃.

Q₁ is located in between the 2^{nd} and the 3^{rd} value and Q₃ is located between the 7^{th} and the 8^{th} value.

The box plot of each data set are shown in the second diagram

The box plots aren't symmetric. Box plot for City A tails on the left (negative skew) and box plot for city B also tails on the left (negative skew).

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12 is what percent of 300?
krek1111 [17]
The percent to 300 out of 12 is 144
6 0
2 years ago
Solve for x*<br> (17x - 8)
djyliett [7]

Answer:x=4

Step-by-step explanation:

This triangle is an equilateral triangle with all angles equal.

Sum of angles in a triangle=180

17x-8+17x-8+17x-8=180

Collect like terms

17x+17x+17x-8-8-8=180

51x-24=180

51x=180+24

51x=204

Divide both sides by 51

51x/51=204/51

x=4

3 0
2 years ago
Credit cards place a three-digit security code on the back of cards. What is the probability that a code starts with the number
ohaa [14]

Answer: 1/10

Step-by-step explanation: because there are 10 numbers (1,2,3,4,5,6,7,8,9, and 0)

7 0
1 year ago
A boat sails on a bearing of 038°anf then 5km on a bearing of 067°.
I am Lyosha [343]

This question is not complete

Complete Question

A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point

Answer:

a)8.717km

b) 54.146°

Step-by-step explanation:

(a)how far is the boat from its starting point.

We solve this question using resultant vectors

= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)

Where

Rcos θ = x

Rsinθ = y

= (4cos38,4sin38) + (5cos67,5sin67)

= (3.152, 2.4626) + (1.9536, 4.6025)

= (5.1056, 7.065)

x = 5.1056

y = 7.065

Distance = √x² + y²

= √(5.1056²+ 7.065²)

= √75.98137636

= √8.7167296826

Approximately = 8.717 km

Therefore, the boat is 8.717km its starting point.

(b)calculate the bearing of the boat from its starting point.

The bearing of the boat is calculated using

tan θ = y/x

tan θ = 7.065/5.1056

θ = arc tan (7.065/5.1056)

= 54.145828196°

θ ≈ 54.146°

7 0
2 years ago
Kim's business earns $10,000 per month. Kim's non-employee expenses are $3,000 per month. If Kim wants $2,000 in profit per mont
MA_775_DIABLO [31]

Answer:

Kim's business earns $10,000 per month.

Kim's non-employee expenses are $3,000 per month.

If Kim wants $2,000 in profit per month, then the maximum amount Kim can spend for employee:

10000 - 3000 - 2000 =5000

If each employee costs $1,000 per month, Kim can recruit 5000/1000 = 5 as the maximum number of employees.

Hope this helps

:)

8 0
2 years ago
Read 2 more answers
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