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inna [77]
2 years ago
3

In basketball, when monica takes her first free throw, she has a 50% chance of scoring. if she takes an additional throw, she ha

s a 75% chance of scoring on this throw if she scored on the immediately previous throw, but only a 25% chance of scoring on this throw if she didn't score on the immediately previous throw. suppose she has to take a set of three free throws in a row, and she doesn't score on the first one. what is the probability that she scores at least once on one of the subsequent two throws?
Mathematics
1 answer:
____ [38]2 years ago
3 0
The probability that she scores at least once on one of the subsequent two throws is 37.5%. It is said that on the first row, she has a 50% chance of scoring. If she takes an additional throw, she has a 75% chance of scoring on this throw if she scored on the immediately previous throw, but only a 25% chance of scoring on this throw if she didn't score on the immediately previous throw. You are asked if she has to take a set of three free throws in a row, and she doesn't score on the first one and so multiply 75% by 50% and you will get 37.5%.

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Round 4.265 to the nearest hundredth
jekas [21]
4.265 rounded to the nearest hundredth is 4.27
3 0
2 years ago
Find all the zeros of the equation 12x^2-64=-x^4
Natalija [7]

Answer: all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

Step-by-step explanation:

Since we  have given that

12x^2-64=-x^4\\\\x^4+12x^2-64=0

We need to find the zeroes of the above equation.

So, we will use  "Split the middle terms" :

x^4+12x^2-64=0\\\\x^4+16x^2-4x^2-64=0\\\\x^2(x^2-16)-4(x^2-16)=0\\\\(x^2-4)(x^2-16)=0\\\\x^2-4=0\ or\ x^2-16=0\\\\\text{ "Using }a^2-b^2=(a+b)(a-b)"\\\\x^2-4=x^2-2^2=(x-2)(x+2)\\\\x^2-16=x^2-4^2=(x+4)(x-4)

So, all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

7 0
2 years ago
In his free time, Gary spends 13 hours per week on the Internet and 11 hours per week playing video games. If Gary has five hour
kotegsom [21]
Bob, bob it always the answer
5 0
2 years ago
An ant has a mass of 0.005 gram. A grasshopper has a mass 0.5 gram..How many ants would it take to equal the mass of 1 grasshopp
lesya692 [45]

Answer:

Step-by-step explanation:

Just divide the larger mass by the smaller.

0.5 / 0.005 = 0.5 / 0.5 * 10^-2 = 1 * 10^2 = 100

It take 100 ants to equal the mass of a grasshopper.

4 0
1 year ago
Samuel was riding in the back seat of the station wagon on the way home after a long and tiring day at the
ki77a [65]

Answer: One fourth of the entire trip.

Step-by-step explanation:

The initial distance is D.

" He fell asleep halfway home."

Then he fells asleep when the distance between his actual position and his house was half of D, or:

D/2.

"He didn't wake up until he still had half as far to go as he had already

gone while asleep."

So he wakes up when his actual position is a fourth of the initial distance:

(D/2)/2 = D/4.

Then if the entire trip has a distance D, and he was sleeping between:

D/2 - D/4 = 2D/4 - D/4 = D/4.

in a trip of a distance D, he was asleep a distance of D/4.

Then, returning to the question:

How much of the entire trip home was Samuel asleep?

This is equal to the quotient between the distance that he travels asleep and the total distance:

r = (D/4)/D = 1/4.

Then he was asleep in 1/4 of the entire trip.

7 0
2 years ago
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