Answer:
<h2>QT = 21</h2><h2>SV = 41</h2>
Step-by-step explanation:
From the diagram, it can be seen that TR is parallel to RV. This means that TR = RV. Given TR = 17 and RV = 3x+2
3x+2 = 17
3x = 17-2
3x = 15
x = 5
RV = 3(5)+2 = 17
QV = 4x+1 = 4(5)+1
QV = 21
Using Pythagoras theorem on ΔQRV to get RQ
QV² = QR²+RV²
21² = QR²+17²
QR² = 21²-17²
QR = 12.33
Using Pythagoras theorem on ΔQRT to get QT
From ΔQRT,
QT² = QR²+TR²
QT² = 12.33²+17²
QR² = 152.0289+289
QT² = 441.0289
QT =21
Since TS = 9(5)-4 = 41
Using Pythagoras theorem on ΔTRS
From ΔTRS,
TS² = RS²+TR²
41² = RS²+17²
RS² = 41²-17²
RS² = 1392
RS = 37.31
Similarly Using Pythagoras theorem on ΔRSV
From ΔRSV,
SV² = RV²+RS²
SV² = 17²+37.31²
SV² = 1681.0361
SV = 41
Answer:

Step-by-step explanation:
The equation to solve is:

1. <u>On the left-hand side </u>use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"
Thus, the left-hand side is:

2. On the <u>right-hand side</u> use "The sum of two logarithms with the same base is the logarithm of the product":
Then, on the right-hand side:

3. <u>Make them equal</u>:

4. Since the two functions are the same, <u>make the arguments equal</u>:

5. <u>Solve the equation</u>:

6 pages of 3; 4 pages of 3 and 3 pages of 2; 2 pages of 3 and 6 pages of 2; 9 pages of 2. There are 4 ways to display his cards. The problem sentence is 18=2x+3y
Answer:
<h3>AC=96 units.</h3>
Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get

Subtracting 6x from both sides, we get


Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of
quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>
<span>A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is 5_ units. The points(-7,5) and (-7,-1</span>) lie on this circle.