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Neko [114]
2 years ago
6

Three cities lie along a perfectly linear route: Springfield, Clarksville, and Allentown. Molly lives in Springfield and works i

n Allentown. She makes it to work using two gallons of gas in her car. Her friend Edgar lives in Allentown and works in Clarksville. It takes Edgar one gallon of gas to get to work. If Molly's car averages 26 miles per gallon, and Edgar's car averages 17 miles per gallon, about how far apart are Springfield and Clarksville?

Mathematics
1 answer:
Ilya [14]2 years ago
4 0
When it says that the cities are routed linearly, it means that these cities are located right next to each other. From the left, the order is Springfield, Clarksville, then Allentown. You have details on the number of gallons and the mileage. To get the distance travelled, just multiply the mileage with the gallons, to cancel out gallons leaving you with the distance in miles.

Now, since Molly travelled from Springfield to Allentown, the total distance she covered is the distance Edward travelled and the unknown distance between Springfield and Clarksville, denoted as x in the picture. So, the equation is then

Molly's distance = x + Edgar's distance
26 miles/gal(2 gal) = x + 17 miles/gal(1 gal)
x = 35 miles

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A certain company's main source is a mobile app. The function h models the company's annual profit (in million of dollars) as a
cricket20 [7]

Answer:

At price 3 and 11, the profit will be $0

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

<em> A certain companies main source of income is a mobile app. The companies annual profit (in millions of dollars) as a function of the app’s price (in dollars) is modeled by P(x)=-2(x-3)(x-11) which app prices will result in $0 annual profit?</em>

My answer:

Given:

  • x is the app price
  • P(x) is the profit earned

If we want to find out the app price that will result in $0 annual profit? It means we need to set the function:

P(x)=-2(x-3)(x-11) = 0

<=> (x-3)(x-11)= 0

<=> x - 3 = 0 or x - 11=0

<=> x = 3 or x = 11

So at price 3 and 11, the profit will be $0

Hope it will find you well.

5 0
2 years ago
Read 2 more answers
David drove a distance (d) of 187 km, correct to 3 significant figures.
Bogdan [553]

Answer: 6.68km/litre

Step-by-step explanation:

Distance(d) = 187km ( to 3 significant figures)

Petrol(p) = 28litres ( to 2 significant figures)

A number, x, rounded to 1 significant figure is 200

Write down the error interval for x

Calculating the lower and upper bound for both 'd' and 'p'

Upper bound 'd' = 187.5km

Lower bound 'd' = 186.5km

Upper bound 'p' = 28.5km

Lower bound 'p' = 27.5km

Therefore,

Petrol consumption (C) = d/p

Upper C = 187.5 / 28.5 = 6.57894

Lower C = 186.5 / 27.5 = 6.781818

Accuracy answer for C = (6.57894 + 6.781818) / 2 = 6.680379

= 6.68km/ litre ( to 3 significant figures)

To achieve a reasonable level of accuracy, the upper and lower bounds of P and D was used to calculate C, which was then averaged.

Using 3 significant figures ensure that we capture the C better, instead of early rounding.

7 0
2 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
Zielflug [23.3K]

Answer:

The 90% confidence interval using Student's t-distribution is (9.22, 11.61).

Step-by-step explanation:

Since we know the sample is not big enough to use a z-distribution, we use student's t-distribution instead.

The formula to calculate the confidence interval is given by:

\bar{x}\pm t_{n-1} \times s/\sqrt{n}

Where:

\bar{x} is the sample's mean,

t_{n-1} is t-score with n-1 degrees of freedom,

s is the standard error,

n is the sample's size.

This part of the equation is called margin of error:

s/\sqrt{n}

We know that:

n=28

\bar{x}=10.41

degrees of freedom = 27

1-\alpha = 0.90 \Rightarrow \alpha = 0.10

t_{n-1} = 1.703

s = 3.71

Replacing in the formula with the corresponding values we obtain the confidence interval:

\bar{x}\pm t_{n-1} \times s/\sqrt{n} = 10.41 \pm 1.70 \times 3.71/\sqrt{28} = (9.22, 11.61)

Download xlsx
8 0
2 years ago
Read 2 more answers
Now find the area of a sail whose hypotenuse is described by the equation Ax+by=c.where A,B are all positive
Dimas [21]

https://www.slader.com/discussion/question/temporaryslug-a4b365bc-a4b365bc/

this should help

8 0
2 years ago
Rework problem 9 from section 3.2 of your text, involving independent and disjoint events. For this problem, assume that Pr[A∪B]
tatuchka [14]

Two events are said to be  Disjoint or Mutually Exclusive if the two events can not  happen at the same time.For example when we throw a die getting an even number is disjoint to getting an odd number.

I.e Probability(A∩B)=0

Let me explain this concept through venn diagram.

Pr[A∪B]=0.7, Pr[A]=0.25

Since events are Disjoint

Pr[A∩B]=0

Pr[A∪B]=Pr[A] + Pr[B]

0.7=0.25 +Pr[B]

0.7-0.25=Pr[B]

⇒Pr[B]=0.45=45/100=9/20

Now events are said to be independent if Pr[A and B]=Pr[A] ×Pr[B]

Events are said to be independent if occurrence of one is not affected by occurrence of other.For example getting multiple of 2 as one event and getting multiple of 3 as second event when we throw a die.

Pr[A∪B]=0.7, Pr[A]=0.25

Pr[A∪B]= Pr[A]+ Pr[B]-Pr[A∩B]

But Pr[A∩B]= Pr[A] ×Pr[B]

⇒Pr[A∪B]= Pr[A]+ Pr[B]- Pr[A] ×Pr[B]

⇒0.7=0.25+p-0.25×p

⇒0.7-0.25=p- 0.25 p

⇒0.45=0.75 p

⇒p= 0.45/0.75

⇒p =3/5


5 0
2 years ago
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