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Neko [114]
2 years ago
6

Three cities lie along a perfectly linear route: Springfield, Clarksville, and Allentown. Molly lives in Springfield and works i

n Allentown. She makes it to work using two gallons of gas in her car. Her friend Edgar lives in Allentown and works in Clarksville. It takes Edgar one gallon of gas to get to work. If Molly's car averages 26 miles per gallon, and Edgar's car averages 17 miles per gallon, about how far apart are Springfield and Clarksville?

Mathematics
1 answer:
Ilya [14]2 years ago
4 0
When it says that the cities are routed linearly, it means that these cities are located right next to each other. From the left, the order is Springfield, Clarksville, then Allentown. You have details on the number of gallons and the mileage. To get the distance travelled, just multiply the mileage with the gallons, to cancel out gallons leaving you with the distance in miles.

Now, since Molly travelled from Springfield to Allentown, the total distance she covered is the distance Edward travelled and the unknown distance between Springfield and Clarksville, denoted as x in the picture. So, the equation is then

Molly's distance = x + Edgar's distance
26 miles/gal(2 gal) = x + 17 miles/gal(1 gal)
x = 35 miles

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snow_tiger [21]

Answer:

Yes. There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Step-by-step explanation:

The sample of the remaining toothpaste is: [.53, .65, .46, .50, .37].

This sample has a size n=5, a mean M=0.502 and standard deviation s=0.102.

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s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{5}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.53-(0.502))^2+...+(0.37-(0.502))^2]}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.001)+(0.022)+(0.002)+(0)+(0.017)]}\\\\\\            s=\sqrt{\dfrac{0.04188}{4}}=\sqrt{0.01047}\\\\\\s=0.102

The 10% of the advertised content is:

0.10\cdot 6.0\;oz=0.6\:oz

Hypothesis test for the population mean:

The claim is that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Then, the null and alternative hypothesis are:

H_0: \mu=0.6\\\\H_a:\mu< 0.6

The significance level is 0.05.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.102}{\sqrt{5}}=0.046

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{0.502-0.6}{0.046}=\dfrac{-0.098}{0.046}=-2.148

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-2.148, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

7 0
2 years ago
Multiple 7/9 to the sum of 8 3/7 and 5 11/14
Brums [2.3K]

\frac{7}{9} \times (8 \frac{3}{7} + 5 \frac{11}{14}) =  \\

\frac{7}{9} \times (8 \frac{6}{14} + 5 \frac{11}{14}   ) =  \\

\frac{7}{9} \times (13 \frac{6 + 11}{14}) =  \\

\frac{7}{9}  \times (13 \frac{17}{14}) =  \\

\frac{7}{9} \times (14 \frac{3}{14}) =  \\

\frac{7}{9} \times ( \frac{14 \times 3 + 3}{14}) =  \\

\frac{7}{9} \times ( \frac{42 + 3}{14}) =  \\

\frac{7}{9} \times ( \frac{45}{14}) =  \frac{7 \times 45}{9 \times 14} =  \frac{5}{2}  \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
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we know that

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<u>the answer is</u>

r=1

7 0
1 year ago
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