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kari74 [83]
2 years ago
4

A building casts a shadow 39 m long. at the same time, the shadow cast by a 59-cm tall pole is 71 cm long. find the height of th

e building.
Mathematics
1 answer:
Romashka [77]2 years ago
3 0

Solving this problem is just pretty straight forward. All we have to do is to use the concept of ratio and proportion.

First, let us say that the height of the building takes the value of variable x.

From the given, we know that the ratio of the building to its shadow is

x : 39 m

And the ratio of the pole to its shadow is

59 cm: 71 cm

To solve for the value of x, we equate the two:

x : 39 = 59 : 71

We know that the symbol of ratio which is “:” also means division, therefore:

x /39 = 59 / 71

x = 59 * 39 / 71

x = 32.41 m

 

Therefore the building is about 32.4 m high

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A teacher needs 70 lengths of string cut to 40cm each. If balls of string are 10 m long, how many balls will be needed.
Genrish500 [490]

Answer:

3

Step-by-step explanation:

A ball is 10 meters. Since 100 centimeters are in a meter, each ball has 100*10 = 1000 centimeters.

The teacher needs 70 strings each 40 centimeters. The total amount they need is 70*40 = 2800 centimeters.

Since a ball has 1000 centimeters, 2800 centimeters will need 3 balls for a total of 3000 centimeters.

5 0
2 years ago
Which are the solutions of x2 = –11x + 4? StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFr
Marysya12 [62]

Answer:

x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}

Step-by-step explanation:

Given the following quadratic equation:

x^2 = -11x + 4

The steps to solve it are:

1. Move the terms to one side of the equation:

x^2+11x- 4=0

2. Apply the Quadratic formula x=\frac{-b\±\sqrt{b^2-4ac} }{2a}.

In this case we can identify that:

a=1\\b=11\\c=-4

Then, substituting these values into the Quadratic formula we get the following solutions:

x=\frac{-11\±\sqrt{11^2-4(1)(-4)} }{2(1)}

x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}

3 0
2 years ago
Read 2 more answers
A cone is cut out of the center of a pyramid with a rectangular base. The rectangular base has side lengths of 15 and 10 units.
Mekhanik [1.2K]

Answer:

Volume of shaded portion = (600 - 36π) units³

Step-by-step explanation:

Volume of the shaded portion = Volume of pyramid - Volume of cone

Volume of pyramid = ⅓*l*w*h

Where,

l = length of base of pyramid = 15 units

w = width of base of pyramid = 10 units

h = height of pyramid = 12 units

Plug in the values to find the volume of the pyramid

Volume of pyramid = ⅓*15*10*12 = 5*10*12 = 600 units³

Volume of Cone = ⅓πr²h,

Where,

r = radius = ½ of diameter = ½ of 9 = 3 units

h = height = 12 units

Volume of Cone = ⅓*π*3²*12 = ⅓*π*9*12

= π*3*12 = 36π units³

Volume of shaded portion = (600 - 36π) units³

3 0
2 years ago
Estimate the unit rate to the nearest hundredth.<br><br> $1.19 per 12fl oz price of 1 fl oz
Korvikt [17]
To find the unit rate you need to divide the 1.19 by 12 so that the ounces would be the price per 1 ounce.
1.19/12 = .099 per ounce
Since we are talking about money your answer needs to be rounded to TWO decimals unless told otherwise.
Rounding .099 would be $ 0.10 per ounce
7 0
2 years ago
Read 2 more answers
Trapezoid STUV with vertices S(-3,6),T(0,7),U(1,4),and V(-5,2): (x,y)&gt;(x+7,y-9)​
hjlf

Answer:

See below

Step-by-step explanation:

<u>Given points:</u>

  • S(-3,6),T(0,7),U(1,4),and V(-5,2)

<u>Translation rule: </u>

  • (x,y) → (x+7,y-9)​

<u>New coordinates by applying the rule:</u>

  • S'(4, -3), T'(7, -2), U'(8, -5), V'(2, -7)

See attached for the graph

The blue trapezoid is STUV and the red one is S'T'U'V'

7 0
2 years ago
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