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shusha [124]
2 years ago
14

imagine that you have a bag containing 10 marbles of different colors. you have drawn a marble, recorded its color and replaced

it fifty times with the following results: 9 purple, 16 orange, 6, yellow and 19 green marbles, make a prediction for how many marbles of each color are in the bag.
Mathematics
1 answer:
zubka84 [21]2 years ago
5 0
I think it might be 50 but im not sure
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How much water must be added to 1 litre of 5% cordial mixture to produce a 4% cordial mixture?
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Answer:

X=1/4L OR 0.25L OR 250ml.

Step-by-step explanation:

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Mr. Johnson is going to buy an 18 3 4 pound turkey for Thanksgiving. The turkey costs $ 2.80 per pound at the grocery store. If
bezimeni [28]

Answer:

10.22 she save

Step-by-step explanation:

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51.1 x 20%=10.22

4 0
2 years ago
A survey found that 73% of adults have a landline at their residence (event A); 83% have a cell phone (event B). It is known tha
4vir4ik [10]

Answer:

3. What is the probability that an adult selected at random has both a landline and a cell phone?

A. 0.58

4. Given an adult has a cell phone, what is the probability he does not have a landline?

C. 0.3012

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that an adult has a landline at his residence.

B is the probability that an adult has a cell phone.

C is the probability that a mean is neither of those.

We have that:

A = a + (A \cap B)

In which a is the probability that an adult has a landline but not a cell phone and A \cap B is the probability that an adult has both of these things.

By the same logic, we have that:

B = b + (A \cap B)

The sum of all the subsets is 1:

a + b + (A \cap B) + C = 1

2% of adults have neither a cell phone nor a landline.

This means that C = 0.02.

73% of adults have a landline at their residence (event A); 83% have a cell phone (event B)

So A = 0.73, B = 0.83.

What is the probability that an adult selected at random has both a landline and a cell phone?

This is A \cap B.

We have that A = 0.73. So

A = a + (A \cap B)

a = 0.73 - (A \cap B)

By the same logic, we have that:

b = 0.83 - (A \cap B).

So

a + b + (A \cap B) + C = 1

0.73 - (A \cap B) + 0.83 - (A \cap B) + (A \cap B) + 0.02 = 1

(A \cap B) = 0.75 + 0.83 - 1 = 0.58

So the answer for question 3 is A.

4. Given an adult has a cell phone, what is the probability he does not have a landline?

83% of the adults have a cellphone.

We have that

b = B - (A \cap B) = 0.83 - 0.58 = 0.25

25% of those do not have a landline.

So P = \frac{0.25}{0.83} = 0.3012

The answer for question 4 is C.

4 0
2 years ago
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