A shipping box in the shape of a cube has edge lengths of 6 inches. it can hold 24 staplers. if the dimensions of a shipping box
are all doubled, how many staplers can the larger box hold? 24 staplers 48 staplers 96 staplers 192 staplers
2 answers:
The correct answer is:
D. 192 staplers.
If the dimensions of a shipping box are all doubled the larger box hold 192 staplers.
We started with one small box. Then we added a box on the side to make it twice as long. Then we added boxes on top to make it twice as tall. Then we added boxes behind it to make it twice as long. That gave us 8 of the small boxes.
Then we multiplied 8 boxes by 24 staplers in each box and got 192 boxes.
Then we multiplied 8 boxes by 24 staplers in each box and got 192 boxes.
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Answer:
Kindly check explanation
Step-by-step explanation:
Given the following information:
First three hours of typhoon: rate of Rainfall. = 25mm per hour
Typhoon slows down for an hour : then Rainfall began again at a constant rate of 20 mm per hour for the next 2 hours
Piecewise function which models Rainfall ad a function of time
Amount of Rainfall as a function of time = f(t)
f(t) = 25t ; if t≤ 3
When typhoon slowed down for an hour :
f(t) = 0;
f(t) = 25*3 ; for t ∈ (3, 4)
Then Rainfall at a constant rate of 20mm for another 2 hours
f(t) = (25 *3) + 20(t - 4) ; for t ∈ (5, 6)
76.48
- 65.00
----------
$11.48
The answer for how much of a markdown would be 15%
The inequality
76.48 is greater than or equal to 65 + 15%
- 65.00
----------
$11.48
The answer for how much of a markdown would be 15%
The inequality
76.48 is greater than or equal to 65 + 15%
Answer:
0.0198 lbs per gallon
Step-by-step explanation:
amount of salt free water = 500 gallons
salt rate in = 1 gal/min
salt rate out = 1 gal/min
amount o salt in brine = 0.25 lb per gallon
Let the amount of salt in the tank be A(t) at any time t.
salt rate in = 0.25 x 1 = 0.25
salt rate out =
The differential equation is given by
where, A(0) = 0
So, the equation becomes
Here the integrating factor is
The solution of the above differential equation is given by
where, C is the integrating constant.
Put, A(0) = 0
C = - 500
As concentration is defined as
Concentration = Quantity / Volume
Now concentration at t = 10 min
Put, t = 10 min
C (10) = 0.0198 lbs per gallon
Thus, teh concentration after 10 min is 0.0198 lbs per gallon.