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aleksley [76]
2 years ago
15

If a random variable X is exponentially distributed with parameter λ=2, then P(X≥1) is equal to

Mathematics
1 answer:
Rasek [7]2 years ago
7 0

Answer:

D. 0.1353

B. 0.0473

Step-by-step explanation:

For an exponentially distributed random variable, the cumulative distribution function is:

P(x\leq a) = 1 - e^{-\lambda a}\\P(x\geq a) = e^{-\lambda a}

with parameter λ=2, then P(X≥1) is equal to:

P(x\geq 1) = e^{-2*1}=0.1353

D. 0.1353

with parameter λ=1.5, then P(2≤X≤4) is equal to

P(2\leq x \leq 4) = P(x \leq 4) - P(x\leq 2)\\P(2\leq x \leq 4) =1 - (e^{-1.5*4}) - (1-(e^{-1.5*2}))\\P(2\leq x \leq 4) = 0.0473

B. 0.0473

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Dan pays £220 per week in rent. His landlord decides to increase the rent by 2.5%. How much rent does he pay now?
Dima020 [189]

Answer:

225.5

Step-by-step explanation:

So, you would start by doing

220 times 2.5% that would equal 5.5

Then you would add

220 + 5.5 = 225.5

Therefore your answer will be 225.5

8 0
2 years ago
Read 2 more answers
A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the pr
Gre4nikov [31]

Answer:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

4 0
2 years ago
The sum of two consecutive even integers divided by four is 189.5
Andre45 [30]
The sum of two consecutive even integers is a+(a+2) and divided by four is
(a+(a+2))/4 = 189.5
(2a+2)/4 = 189.5
2a+2 = 189.5 * 4
2a+2 = 758
2a = 758 - 2
2a = 756
a = 756/2 = 378
first number is a = 378
second number is a+2 = 378+2 = 380
6 0
2 years ago
4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr
Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single  bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = 3(4)^{5} =3072

ii) II bacteria P = 3(4)^{4} =768

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

3(4)^{10}- 3(4)^{8} =2949120

c) i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

i) P=3 (4)^{36/12}=192

The rate may not be constant for a longer time.  Hence this may not be accurate.

e) when splits into 2, we get

P=P_o (2^t) where P0 is initial and t = interval of time

7 0
2 years ago
Which expression is an equivalent expression of 12x + 10 + 4y?
Nutka1998 [239]
-3x-2.5=y would be an equivalent to that equation
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2 years ago
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