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2 years ago

What is unit form of (4 ten thousand 8 hundreds)÷10

Mathematics

2 answers:

Dafna1 [17]2 years ago

5 0

The answer of this question is quite simple we can write the question into unit form very easily the unit form is 4,080

Further Explanation:

Data:

(4 ten thousand and 8 hundred) / 10.

Solution:

Sol.

= ( 4 ten thousand and 8 hundred ) / 10

= ( 4 0 8 0 0 ) / 1 0.

= 4 , 0 8 0

Answer :

The unit form of the (4 ten thousand and 8 hundred) / 10 is 4,080. As you see How easily I find out the answer and the unit form you can also find ou the unit form of any question by following this method. I have done this as easily as I can hope you can understand the solving procedure Thanks.

If you have understand this one question then you can easily find ou the unit form.

Procedure:

As 4 is a ten thousand place and 8 is at 8 hundreds place and then divided by 10 which cancel out the one zero and remains behind a 4080 which is our require unit form hop you understand.

Answer Details:

Subject: Mathematics

Level: College.

Key Words:

Data:

Solution :

Answer :

Procedure

For further Evaluation:

brainly.com/question/6362387

brainly.com/question/12938965

sukhopar [10]2 years ago

3 0

We have to calculate (4ten thousands 8 hundreds) : 10 and to show it in the unit form.
4 ten thousands 8 hundreds = 40,000 + 800 = 40,800
40,800 : 10 = 4,080
Answer:
4,080 in the unit form.

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev

Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 30.05 inches

$\sigma$ = standard deviation = 0.2 inches

n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches) = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z < 3) = 0.99865

P(X bar <= 30.25) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches) = 0.99865 - 0.97725

= 0.0214

7 0

2 years ago

On a rectangular soccer field, Sang is standing on the goal line 20 yards from the corner post. Jazmin is standing 99 yards from

Anna007 [38]

Okay, so Sang is standing 20 yards away from one corner, and Jazmin is standing 99 yards away from the same corner. If this is a rectangle (I like visuals, so I'll use them to explain), then:

99ft
A ------------------------- B
   |    |
20 ft |    |
   |    |
C -------------------------- D

The question is asking you to solve for the diagonal line between points C and B. If you imagine a line there, you actually have the rectangle split into two triangles. So if you have triangle ABC, side CB would be the longest line, or the hypotenuse. That means you can use the Pythagorean Theorem to solve the problem.

A^2 + B^2 = C^2
99^2 + 20^2 = C^2
9,801 + 400 = C^2
10,201 = C^2

Now you solve for the square root of 10,201 to get C.

sqr (10,201) = C
C = 101 yards

3 0

2 years ago

Mr. Johnson currently has a square garden. It is in his garden and into a range of 5 feet shorter than three times shorter than

Vlad [161]

Answer:

The Dimension of new garden is $25 \ feet\ \times 10\ feet.$