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kvasek [131]
2 years ago
10

Here is a widely publicized, true story about how failing to convert units resulted in a huge loss. in 1998, the mars climate or

biter probe, instead of entering orbit, crashed into the surface of mars. the resulting inquiry revealed that nasa navigators had been making minor course corrections in si units, whereas the software written by the probe's makers implicitly used british units. in the united states, most scientists use si units, whereas most engineers use the british (or imperial) system of units. (interestingly, british units are not used in the united kingdom.) for these two groups to be able to communicate with each other, unit conversions are necessary. the unit of force in the si system is the newton, n, which is defined in terms of basic si units as 1n=1(kg⋅m)/s2. the unit of force in the british system is the pound, lb, which is defined as 1lb=1(slug⋅ft)/s2, where the slug is the unit of mass.
Physics
1 answer:
Volgvan2 years ago
7 0
This is the reason why dimensional analysis is very important. It is a technique used that only involves operations with units. You disregard the quantities first. The concept is to make sure that the final answer of your calculations must be consistent of what is asked. Similar units are cancelled when they appear both on the numerator and denominator side. If the mathematicians used this, they could've prevented the crash from happening. What good would the calculations bring if you are not consistent with the units?
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A machine part is vibrating along the x-axis in simple harmonic motion with a period of 0.27 s and a range (from the maximum in
Gnoma [55]

Answer:

x = -1.437 cm

Explanation:

The general equation for position of Simple harmonic motion is given as:

x = A sin(\omega t)          ........(1)

where,

x = Position of the wave

A = Amplitude of the wave

ω = Angular velocity

t = time

In this case, the amplitude is just half the range,

thus,

A =\frac{3cm}{2}=1.5cm  (Given range = 3cm)

A = 1.5 cm  

Now, The angular velocity is given as:

\omega=\frac{2\pi}{T}

Where, T = time period of the wave =0.27s (given)

\omega=\frac{2\pi}{0.27s}

or

\omega=23.27s^{-1}

so, at time t = 55 s, the equation (1) becomes as:

x = 1.5 sin(23.27\times 55)

on solving the above equation we get,

x = -1.437 cm

here the negative sign depicts the position in the opposite direction of +x

5 0
2 years ago
With your hand parallel to the floor and your palm upright, you lower a 3-kg book downward. If the force exerted on the book by
Stells [14]
For Newton's second law, the resultant of the forces acting on the book is equal to the product between the mass of the book and its acceleration:
\sum F = ma (1)

There are only two forces acting on the book:
- its weight, directed downward: mg
- the force exerted by the hand on the book, of 20 N, directed upward

so, equation (1) becomes
mg - F = ma
from which we can calculate the book's acceleration, a:
a= g -  \frac{F}{m}= 9.81 m/s^2 - \frac{20 N}{3 kg}=3.14 m/s^2
7 0
2 years ago
Read 2 more answers
(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i
ddd [48]

Answer:

a) P = 370.993\,kPa, b) F = 25.948\,kN

Explanation:

a) The absolute pressure at a depth of 27.5 meters is:

P = P_{atm} + P_{man}

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (27.5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

P = 370.993\,kPa

b) The force exerted by the water is:

F = (P - P_{atm})\cdot A

F = (370.993\,kPa-101.3\,kPa)\cdot \left(\frac{\pi}{4} \right)\cdot (0.35\,m)^{2}

F = 25.948\,kN

5 0
2 years ago
Read 2 more answers
A spacecraft of the Trade Federation flies past the planet Coruscant at a speed of 0.610 c. A scientist on Coruscant measures th
mamaluj [8]

Answer:

the length of the now stationary spacecraft = 89.65m

Explanation:

In contraction equation, Length contraction L is the shortening of the measured length of an object moving relative to the observer’s frame.

Thus, it has a formula;

L = L_o(√(1 - (v²/c²))

Where in this question;

L = 71m and v = 0.610 c

Thus;

71 = L_o (√(1 - ((0.61c)²/c²))

c² will cancel out to give;

71 = L_o (√(1 - 0.61²)

71 = L_o (√(1 - 0.61²)

71 = 0.792L_o

L_o = 71/0.792

L_o = 89.65m

6 0
2 years ago
3. In 1989, Michel Menin of France walked on a tightrope suspended under a
Tamiku [17]

Answer: 80m

Explanation:

Distance of balloon to the ground is 3150m

Let the distance of Menin's pocket to the ground be x

Let the distance between Menin's pocket to the balloon be y

Hence, x=3150-y------1

Using the equation of motion,

V^2= U^s + 2gs--------2

U= initial speed is 0m/s

g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s

40m/s is contant since U (the coin is at rest is 0) hence V =40m/s

Slotting our values into equation 2

40^2= 0^2 + 2 * 10* (3150-y)

1600 = 0 + 63000 - 20y

1600 - 63000 = - 20y

-61400 = - 20y minus cancel out minus on both sides of the equation

61400 = 20y

Hence y = 61400/20

3070m

Hence, recall equation 1

x = 3150 - 3070

80m

I hope this solve the problem.

6 0
2 years ago
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