Answer:
Step-by-step explanation:
-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(- +
j)
-1.2i - 1.6j + 0.6i - 1.5j - i + 0.5j
Converting to fraction form;
<u>Solving the i part;</u>
=
<u>Solving the j part;</u>
j
So -0.4a - o.3b + 0.2d = -
Let the random variable x have a discrete uniform distribution on the integers 8 ≤ x ≤ 10. determine the mean, μ, and variance,
σ2, of x.
1 answer:
The discrete uniform distribution is on the interval 8 ≤ x ≤ 10.
Therefore the probability density function (shown in the figure) is
P(x) = 1/3 = 1/3 for x = 8, 9, 10
= 0 otherwse
The mean is μ = 1/3.
The variance is
σ² = Σp(x) (x- μ)²
Because x - μ = 0 for x = 8,9,10, therefore
σ² = 0
Answer:
μ = 1/3
σ² = 0
Therefore the probability density function (shown in the figure) is
P(x) = 1/3 = 1/3 for x = 8, 9, 10
= 0 otherwse
The mean is μ = 1/3.
The variance is
σ² = Σp(x) (x- μ)²
Because x - μ = 0 for x = 8,9,10, therefore
σ² = 0
Answer:
μ = 1/3
σ² = 0
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