Answer: Option (d) is the correct answer.
Explanation:
The reaction given is as follows.
From this equation, it can be seen that chlorine gas reacts with aqueous potassium bromide solution to give aqueous potassium chloride and liquid bromine.
Also, chlorine is more reactive than bromine because it is smaller in size than bromine and has less shielding effect so it will readily accept an electron. Thus, chlorine displaces bromine from potassium bromide solution.
Thus, we can conclude that chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.
Answer:
The enthalpy change for the given reaction is 424 kJ.
Explanation:
We have :
Enthalpy changes of formation of following s:
(standard state)
The equation for the enthalpy change of the given reaction is:
=
=
The enthalpy change for the given reaction is 424 kJ.
Answer:
There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C
Explanation:
To decrease the temperature of the solution there are necessaries:
4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y
8368J + 83,68J/gX = Y <em>(1)</em>
Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.
Also, the energy Y will be:
Y = 25700J/mol×X
Y = 321J/g X <em>(2)</em>
Replacing (2) in (1)
8368J + 83,68J/g X = 321J/g X
8363J = 237,32J/gX
<em>X = 35,2g</em>
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Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C
I hope it helps!