The answer is B. (an increase in inbreeding) hope this helped !!
Answer:
True
Explanation:
Oogenesis includes the formation of one egg cell from a single oocyte or egg mother cell. The diploid primary oocytes in the ovaries enter into the first meiotic division and form a haploid secondary oocyte and a haploid first polar body. After fertilization, the secondary oocytes complete the meiosis-II and forms one large ovum and a second polar body. The ovum formed by meiosis-II is much larger than the second polar body due to the unequal distribution of cytoplasm during meiosis-II. This imparts enough amount of cytoplasm in the zygote to support the mitosis without any cell growth.
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
This is because if the two metabolic processes were to be active at at the same time;
Two molecules of<u> ATPs</u> and <u>Guanosine triphophate </u>(sometimes used for energy transport) <u>will be expended per each cycle, with no compensatory rate of replacements present at the moment in the cell,this affects cell metabolism for energy availability</u>
<u>2</u> Both<u> Glycolysis and Gluconeogensis </u>are both<u> exergonic processes in cells. </u> The heat energy liberated from these Calorinogenic effects will be higher than what the natural thermodynamic barrier of cells can withstand. Consequently; the heat will raise temperature of the cells affecting metabolic activities of hormones and enzymes which are (proteins) ,and easily denature by high temperatures.
However, in muscles cells,gluconeogeneis is a compensasory process of Glycolysis. This because during active exercise with high metabolic demand in muscles cells, glucose is rapidly metabolise to to pyruvate,(but not at the rate that the Citric acid cycle can metabolise) for Lactic acid production by muscles cells for energy production. Pyruvate must be broken down rapidly so that NAD+ will be available for Glycolysis to continue. Therefore to sustain Glycolysis at this rate continuous supply of glucose is supplied from Gluconeogenesis.
Answer: Survival rate up to start of April = 76.67%
Explanation: size of colony = 150mice.
Size of colony in February =125mice.
Size of colony in march = 115 mice.
1. Survivorship rate in February
= Size of colony / size in February *100.
= 122 / 150 * 100
= 83.33% to the nearest hundredth
2. Survivorship rate in march
= Size of colony / size in march *100.
= 115/150 * 100
= 76.67% to the nearest hundredth.
