If I have a stack of pennies. And I have to tell that without counting whether there are even number of pennies or odd.
Even numbers are the numbers which are divisible by 2 and odd numbers are the numbers which are not divisible by 2.
Then I will put the given pennies in 2 rows and then I will match them to form a pair of 2 pennies.
After matching, if there is 1 penny left over, then there is an odd number of pennies and if all the pennies have a match,then there is an even number of pennies.
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
Are you sure you didn’t miss anything while writing the question?
Cause we have nothing to go off. Everybody types differently so there is no way for us to say how long he typed for, unless we were given aprox how many words he wrote in a minute or something
Compatible numbers are those closest to these numbers- 65 rounded to the nearest tens is 70, and adding that to 150 we get B. 210.
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Hope this helps!
Answer:
Total number of dogs is 5.
Step-by-step explanation:
Cups of food each dog gets=
Here,each dog eats two-third cups of dog food.
Amount of dog food used=
A total of three and one-third cups of food is used up.
Let the number of dogs be x.
To find the number of dogs,divide total dog food used by the amount of dog food eaten by each dog.
Hence, x =
x =
x =5