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horsena [70]
3 years ago
5

A small business earns a profit of $6500 in January and $17,500 in May. What is the rate of change in profit for this time perio

d? Please help :(
Mathematics
1 answer:
Mashutka [201]3 years ago
3 0
So in a matter of 3 months, the profit went up 11,000$ ( you would subtract 17,500 from 6500 to get that number.) Once you get that you would divide it by 3 because there are 3 months in-between. You want to get the profit for one month to learn the rate. So your answer would be 3666 dollars profit a month.
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If you have a stack of pennies without counting them how do you know if there is an even or odd number of them
zavuch27 [327]

If I have a stack of pennies. And I have to tell that without counting whether there are even number of pennies or odd.

Even numbers are the numbers which are divisible by 2 and odd numbers are the numbers which are not divisible by 2.

Then I will put the given pennies in 2 rows and then I will match them to form a pair of 2 pennies. After matching, if there is 1 penny left over, then there is an odd number of pennies and if all the pennies have a match,then there is an even number of pennies.

5 0
2 years ago
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

6 0
2 years ago
Kenny types 280 words. How long did he <br> type for?<br> A.4<br> B. 5<br> C.6<br> D. 7
zlopas [31]
Are you sure you didn’t miss anything while writing the question?

Cause we have nothing to go off. Everybody types differently so there is no way for us to say how long he typed for, unless we were given aprox how many words he wrote in a minute or something
5 0
2 years ago
Read 2 more answers
Which of the following is the estimated sum of sixty-five and one-hundred-fifty using compatible numbers?A.200B.210C.220D.230
posledela
Compatible numbers are those closest to these numbers- 65 rounded to the nearest tens is 70, and adding that to 150 we get B. 210.
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Hope this helps!
6 0
2 years ago
Elena is feeding her neighbor's dogs each dog gets two thirds cup of dog food and she uses three and one third cups of food how
MrRa [10]

Answer:

Total number of dogs is 5.

Step-by-step explanation:

Cups of food each dog gets=\frac{2}{3}

Here,each dog eats two-third cups of dog food.

Amount of dog food used=\frac{10}{3}

A total of three and one-third cups of food is used up.

Let the number of dogs be x.

To find the number of dogs,divide total dog food used by the amount of dog food eaten by each dog.

Hence,  x  =\frac{\frac{10}{3} }{\frac{2}{3} }

              x  =\frac{10}{2}

               x  =5

5 0
2 years ago
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