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inysia [295]
2 years ago
7

A regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during

the rotation?
1. 2
2. 4
3. 6
4. 8
Mathematics
1 answer:
True [87]2 years ago
4 0
Hello there!

The correct answer is D. 8.

Hope This Helps You!
Good Luck :)
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Given: m∠ATB = 63°, arc AB = 115° Find: arc DC
Flura [38]

Answer:

The measure of arc DC is 11\°

Step-by-step explanation:

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

m\angle ATB=\frac{1}{2}[arc\ AB+arc\ DC]

substitute the given values

63\°=\frac{1}{2}[115\°+arc\ DC]

126\°=[115\°+arc\ DC]

arc\ DC=126\°-115\°=11\°

6 0
2 years ago
893 hundreds x 85 tens =
cricket20 [7]
The answer is 75,905
8 0
2 years ago
Read 2 more answers
Consider a data set with at least three data values. Suppose the highest value is increased by 10 and the lowest is decreased by
bulgar [2K]

Answer:

a. Mean doesn't change.

b. Median doesn't change.

c. Mode can change.

Step-by-step explanation:

Let us assume the data set with 10 observations

{2,6,4,3,2,6,4,9,4,7}.

Arranging data set in ascending order

{2,2,3,4,4,4,6,6,7,9}

mean=2+2+3+4+4+4+6+6+7+9/10=4.7

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Mode

The most repeated value is 4. So, mode is 4 for assumed data.

Increasing highest value by 10 and decreasing lowest value by 10

{-8,2,3,4,4,4,6,6,7,19}

a.

mean=-8+2+3+4+4+4+6+6+7+19/10=4.7

Mean doesn't change

b.

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Median doesn't change

c.

Most occurring value is still 4. But mode can change if the value the highest value becomes most concurring value.

5 0
2 years ago
Read 2 more answers
a grocery store sells a bag of 4 lemons for $0.79. Which pricing option would result in the same unit price for each lemon
yaroslaw [1]
.79/4= .197. Or 20 cents each
5 0
2 years ago
Bethany,Lauren,Amanda,and David all meet at Family reunion. They are comparing their ages. They have found that Laura is 13 year
bazaltina [42]
The second system of equations, 

\left \{ {{y=\frac{x^2}{2}+\frac{13}{2}x} \atop {y=x^2-27x+129}}
is correct.

We know that Bethany's age is x.  Since Laura is 13 years older, her age is x+13.  The product of their ages is equal to twice Amanda's age, and Amanda's age is y.  This gives us:
x(x+13) = 2y

Using the distributive property, we have 
x²+13x=2y

Dividing everything by 2 (to isolate y), we have:
x²/2 + (13/2)x = y

If we take 20 years off of Bethany's age, it is now represented as x-20.  Taking 20 years off of Laura's age would be (x+13-20) or x-7.  The product of their ages now is equal to David's age; David is 11 years older than Amanda, so his age is y+11.  This gives us:

(x-20)(x-7)=y+11

Multiplying the binomials we have:"
x*x - 7*x - 20*x - 20(-7) = y+11
x²-7x-20x--140=y+11
x²-27x+140=y+11

To isolate y, subtract 11 from both sides:
x²-27x+140-11 = y+11-11
x²-27x+129 = y
7 0
2 years ago
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