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zhannawk [14.2K]
1 year ago
9

describe briefly one scenario where records stored in a computer frequently need to be searched. state why the searches may be c

arried out
Computers and Technology
2 answers:
Nadya [2.5K]1 year ago
8 0

Answer

The scenarios are when;

• The spring input is invalid

• The source is not attached to the search engine in use

Explanation

A collection of saved data, organized for easy retrieval is called a database. Each data item is stored in a position relative to the others. A proper retrieval requires searching sequentially through the whole file record using a proper search word.


Gnoma [55]1 year ago
4 0
Because the string is invalid or your source is not attached to your search engine.
You might be interested in
Create an application named SalesTransactionDemo that declares several SalesTransaction objects and displays their values and th
crimeas [40]

Answer:

Explanation:

The following code is all written in Java, first I will add the object initialization and declaration code that can be added to the main method of any program. Then I have also written the entire SalesTransaction class as the question was not clear as to exactly which was needed.

//Object Creation to copy and paste into main method

SalesTransaction sale1 = new SalesTransaction("Gabriel", 25, 5);

SalesTransaction sale2 = new SalesTransaction("Daniela", 5);

SalesTransaction sale3 = new SalesTransaction("Jorge");

//SalesTransaction class with three constructors

package sample;

class SalesTransaction {

   String name;

   int salesAmount, commission;

   private int commissionRate;

   public SalesTransaction(String name, int salesAmount, int rate) {

       this.name = name;

       this.salesAmount = salesAmount;

       this.commissionRate = rate;

       commission = salesAmount * rate;

   }

   public SalesTransaction(String name, int salesAmount) {

       this.name = name;

       this.salesAmount = salesAmount;

       this.commissionRate = 0;

   }

   public SalesTransaction(String name) {

       this.name = name;

       this.salesAmount = 0;

       this.commissionRate = 0;

   }

}

8 0
1 year ago
The number of operations executed by algorithms A and B is 40n2 and 2n3, respectively. Determine n0 such that A is better than B
Tom [10]

Answer:

Given that:

A= 40n^2

B = 2n^3

By given scenario:

40n^2=2n^3

dividing both sides by 2

20n^2=n^3

dividing both sides by n^2 we get

20 = n

Now putting n=20 in algorithms A and B:

A=40n^2

= 40 (20)^2

= 40 * (400)

A= 16000

B= 2n^3

= 2 (20)^3

= 2(8000)

B= 16000

Now as A and B got same on n = 20, then as given:

n0 <20 for n =20

Let us take n0 = 19, it will prove A is better than B.

We can also match the respective graphs of algorithms of A and B to see which one leads and which one lags, before they cross at n= 20.

8 0
2 years ago
Produce a list named prime_truths which contains True for prime numbers and False for nonprime numbers in the range [2,100]. We
LenKa [72]

Answer:

  1. def is_prime(n):
  2.    for i in range(2, n):
  3.        if(n % i == 0):
  4.            return False  
  5.    return True  
  6. prime_truths = [is_prime(x) for x in range(2,101)]
  7. print(prime_truths)

Explanation:

The solution code is written in Python 3.

Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.

Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.

After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).

3 0
2 years ago
Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:
horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed.  So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

          = 0.00833 * 100

          = 0.833 ms

So there is  1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d)  Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0
2 years ago
You have been employed as a technical consultant to a computer shop chain. You are given the task of creating a short consumer b
brilliants [131]

Answer:

The five factors to consider when trying to choose between a Solid State Drive, a Hard Disk Drive and, an External Hard Disk Drive are:

  1. Read/Write Speed
  2. Weight
  3. Power Consumption
  4. Cost
  5. Storage Capacity

  • Solid State Drives (SSDs) are typically lighter in weight, faster and do not consume much power.
  • Hard Disk Drives are relatively cheaper than SSDs. They also come with higher storage capacities but are more power-hungry and slower because they rely on mechanical/moving parts to read and write data.
  • External HDDs are the cheapest of the three. They are not internal which is a major drawback given the additional weight. However, they come with gargantuan storage capacities that make you want to rethink having one. Besides, unlike SSDs, you can easily get them in computer accessories shops offline or online.

Cheers!

3 0
2 years ago
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