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jeyben [28]
2 years ago
12

If p(x) = 5(x^2+1)+16 what is the value of p(11)

Mathematics
2 answers:
olya-2409 [2.1K]2 years ago
7 0

Answer:

p(11) = 626.

Step-by-step explanation:

Given  : p(x) = 5(x²+1)+16.

To find :  what is the value of p(11).

Solution : We have given  p(x) = 5(x²+1)+16.

For x = 11.

p(11) = 5((11)²+1)+16.

p(11) = 5 ( 121 + 1 ) +16.

p(11) = 5 (122) + 16.

p(11) =  610 + 16.

p(11) = 626.

Therefore,  p(11) = 626.

Karo-lina-s [1.5K]2 years ago
4 0
5(11^2+1)+16

5(121+1)+16

5(122)+16

610+16

p(11)=626
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Step-by-step explanation:

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