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levacccp [35]
2 years ago
13

renaldo catches the bus at 4:00 onto ride 3.2 miles from his house to the dentist office. He arrives at 4:30 p.m for one hour ap

pointment then he will ride a bus traveling at the same rate of speed 4.8 miles to the soccer feild. Will he be on time for his 6:30 p.m soccer practice? explain
Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0

Answer:

Yes, Renaldo will be reach on time for his Soccer practice.

Step-by-step explanation:

For traveling for 3.2 miles bus takes 30 minute times.

So, traveling a 1-mile bus will take 30 ÷ 3.2 minutes.

Now, Renaldo reaches the dentist's office at 4:30 p.m.

Then he has an appointment for 1 hour

So, Renaldo leaves the dentist's office at 5:30 p.m.

Now he has to travel 4.8 miles, it will take time = 4.8\times\frac{30}{3.2} = 45 minutes

So, Renaldo will reach Soccer field at

5 hours 30 minute + 45 minutes = 6 hours 15 minutes = 6:15 p.m

Hence, Renaldo will reach Soccer field before 6:30 p.m.

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You paid $36.20 for a sweater that originally cost $90.50. What percentage of the original price was the sweater on sale for?You
marin [14]

Answer:

32.761 %

Step-by-step explanation:

Percentage is any fraction or ration expressed as a fraction of 100.

Percentage is calculated using formula

If A has to be expressed as percentage of then it can be expressed as

A/B * 100 in percentage form .

For given problem price paid for sweater = $36.20

original price of sweater = $90.50

Problem is to express percentage of price for which sweater was on sale for.

It can be mathematically  expressed as

what is 36.20% of 90.5

percentage of price for which sweater was on sale for = (price paid for sweater/original price of sweater  ) * 100

It can be mathematically  expressed as

what is 36.20% of 90.5

=>  ($36.20/$90.50 )* 100= 32.761.

32.761 % of the original price sweater was on sale for.

For better understanding ,It can also be said that that if the original price of sweater had been $100, then you would have got it at $32.761 .

4 0
2 years ago
Aisha helps out at a petting zoo over the summer. She makes some changes where the animals are kept.
adoni [48]
I believe the awnser is A
3 0
2 years ago
A ball is thrown from a height of 43 meters
AveGali [126]
When the ball will hit the ground, the height will be zero. So we need to replace h with 0 in our equation, and solve for t:
0=43-4t-5t^{2}
-5t^{2}-4t+43=0
To solve this equation we are going to use the quadratic formula: t= \frac{-b(+/-) \sqrt{b^{2}-4ac} }{2a}.
From our height equation, we can infer that a=-5, b=-4, and c=43. So lets replace those values in our quadratic formula to find t
t= \frac{-(-4)(+/-) \sqrt{(-4)^{2}-4(-5)(43)} }{2(-5)}
t=- \frac{5}{8} - \frac{ \sqrt{713} }{8} or t=- \frac{5}{8} + \frac{ \sqrt{713} }{8}
t=-3.96 or t=2.71
Since time cannot be negative, t=2.71 is the solution of our equation.

We can conclude that the ball will hit the ground after 2.71 seconds.
4 0
2 years ago
Estimates show that there are 1.4x10^8 pet fish and 9.4x10^6 pet reptiles in the United States. How many pet fish and reptile pe
azamat

Answer:

There are total number of pet fish and reptile pets are 1.49\times 10^8.

Step-by-step explanation:

Number of pet fish are 1.4\times 10^8 and the number of pet reptiles are 9.4\times 10^6.

It is required to find the total number of pet fish and reptile pets in the United States. It can be done by simply adding the above numbers such that total numbers are given by :

T=1.4\times10^{8}+9.4\times10^{6}\\\\T=149400000\\\\T=1.49\times 10^8

So, there are total number of pet fish and reptile pets are 1.49\times 10^8.

8 0
2 years ago
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
fomenos
A dilation is a transformation D_{o,k}(x,y), with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'. The center O is a fixed point, P' is the image of P, points O, P and P' are on the same line.

In a dilation of D_{o, \frac{1}{2} }(x,y), the scale factor, \frac{1}{2} is mapping the original figure to the image in such a way that the distances from O to the vertices of the image are half the distances from O to the original figure. Also the size of the image is half the size of the original figure.

Therefore, <span>If D_{o, \frac{1}{2} }(x,y) is a dilation of △ABC, the truth about the image △A'B'C'</span> are:

<span>AB is parallel to A'B'.

D_{o, \frac{1}{2} }(x,y)=( \frac{1}{2}x,  \frac{1}{2}y)

The distance from A' to the origin is half the distance from A to the origin.</span>
3 0
2 years ago
Read 2 more answers
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