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stiv31 [10]
2 years ago
14

What is the net ionic equation of the reaction of mgso4 with sr(no3)2? express you answer as a chemical equation including phase

s?
Chemistry
2 answers:
lana [24]2 years ago
6 0
<span>MgSO4 and Sr(NO3)2 are both soluble, so the ionic equation would look like this. Mg+2 + SO4-2 + Sr+2 + 2NO3-1 ---> Mg+2 + 2NO3-2 + SrSO4 SrSO4 is insoluble. Now Mg and 2NO3 are on both sides, so cross them out, the net ionic equation is SO4-2 + Sr+2 ----> SrSO4</span>
alexandr402 [8]2 years ago
6 0

The Net Ionic equation for the reaction between MgSO4 with Sr(NO3)2 is given by;  

Sr ⁺²(aq) + SO₄⁻²(aq) → SrSO₄(s)

<h2>Further Explanation</h2><h3>Net ionic equations </h3>
  • Net ionic equations that do not include all ions that are present in the reactants and products.
  • The equations only includes the ions that are involved in the reaction.
  • The ions that are not involved in a chemical reaction are called spectator ions and are cancelled out while writing ionic equations.
  • Reaction between MgSO4 with Sr(NO3)2 is an example of a displacement reaction.
  • During the reaction magnesium ion bonds with nitrate ions and forms magnesium nitrate, while strontium ion bonds with sulfate ion to form strontium sulfate.

That is:

MgSO₄(aq) + Sr(NO₃)₂(aq) → Mg(NO₃)₂(aq) + SrSO₄(s)

  • Mg ion remains in aqueous form in both magnesium nitrate and magnesium sulfate and therefore cancelled out since it is a spectator ion.
  • Additionally, Nitrate ion is also a spectator ion as it does not change state thus, also cancelled out while writing net ionic equation.

Therefore; the ionic equation required will be;

Sr ⁺²(aq) + SO₄⁻²(aq) → SrSO₄(s)

<h3>Keywords: Net ionic equations</h3>

<h3>Learn more about; </h3>
  • Net ionic equation: brainly.com/question/11510759
  • Spectator ions: brainly.com/question/4153338
  • Example of net ionic equations; brainly.com/question/11482104

Level: High school

Subject: Chemistry

Topic: Chemical equation

Sub-topic: Net ionic equations

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Solution :

The balanced cell reaction will be,  

Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)

Here magnesium (Mg) undergoes oxidation by loss of electrons, thus act as anode. Cadmium (Cd) undergoes reduction by gain of electrons and thus act as cathode.

Now we have to calculate the concentration of unknown Cd^{2+}.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Mg^{2+}]}{[Cd^{2+}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

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Now put all the given values in the above equation, we get

concentration of unknown Cd^{2+}.

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2 years ago
How many moles are there in 3.612 X 10^24 molecules of phosgene (COCL2)
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Answer:

Explanation:

No of molecules = 3.612*10(24)

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Answer:

Explanation:

A carbon-12 atom has a mass defect of 0.09564 amu. What is its nuclear binding energy? Round to 3 significant figures. x 10 J per carbon-12 atom

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