Ask question

Ask question

All categories

1 year ago

8

The atmospheric pressure at sea level is 14.7 lb/in2. This pressure is reduced by half for each 3.6 miles above sea level. Which

graph correctly identifies the amount of atmospheric pressure based on height, in miles, above sea level?
Please respond with the answer A B C or D they are in order.

2 answers:

Korvikt [17]1 year ago

8 0

<u>Solution-</u>

The atmospheric pressure at sea level = 14.7 lb/in²

Pressure gets reduced by half for each 3.6 miles we move up.

Taking,

x = miles above the sea-level

y = pressure in lb/in²

0 14.7

3.6 7.35

7.2 3.675

10.8 1.8375

It can be observed that both the variables are in inverse proportion as the distance from sea-level increase the pressure decreases.

As only the second graph satisfies the points and inverse proportional condition, so that is the correct graph.

By plotting the graph in excel taking these data set, the following plot was obtained.

baherus [9]1 year ago

4 0

At 3.6 miles above see level the pressure is reduced to 1/2 * 14.7 = 7 .35 lbs / in^2

B is the correct graph

You might be interested in

The 230 people at a party decide to order pizza for a snack. If each pizza has 8 slices, how many pizzas should they order so th

Nat2105 [25]

$230 : 8=28.75 \approx 29 \\ \\ the \ answer \ is \ variant\ D$

6 0

1 year ago

Read 2 more answers

Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

tigry1 [53]

Answer:

$M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ . Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

$y=k\cdot x + b$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$k$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $b = 1$ , $x = 1$ and $y = 3$ , then we clear slope and solve the resulting expression:

$k = \frac{y-b}{x}$

$k = \frac{3-1}{1}$

$k = 2$

Then, we conclude that point $M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ , whose graph is presented below.

3 0

1 year ago

The Colossus Ferris wheel debuted at the 1984 New Orleans World’s Fair. The ride is 180 ft tall, and passengers board the ride a

Makovka662 [10]

Answer:

$T=\frac{2}{3}$

Interpretation:

It means that Passenger will reach to same height after each 2/3 minutes

Step-by-step explanation:

We are given height function as

$h=82.5sin(3\pi(t+0.5))+97.5$

where

h is the height above the ground

t is the time

we can compare it with standard equation

$y=Asin(B(t+C))+D$

Period formula is

$T=\frac{2\pi}{B}$

now, we can compare and find B

$B=3\pi$

we can find period

$T=\frac{2\pi}{3\pi}$

$T=\frac{2}{3}$

Interpretation:

It means that Passenger will reach to same height after each 2/3 minutes

5 0

1 year ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

1 year ago

For the first year of his car insurance policy, Tom pays $77 per month. Tom's payments are reduced to $65 per month in the secon

Tcecarenko [31]

77/65=1.18
round 1.18 to 1.2

6 0

1 year ago

Read 2 more answers