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2 years ago

An 8 foot length of 4 inch wide crown molding costs $16. How much will it cost to buy 40 feet of crown molding?

1 answer:

6 0

Converting feet to inches, 8*12=96 and 96*4=384. Next, 40*12=480. Since 384*x (if x represents the cost per inch of crown molding)=16*100=1600 cents due to that for every inch, we add x amount of money, we can find x to be 1600/384=800/192=400/96=200/48=100/24=50/12=25/6 by simply dividing both the numerator and denominator by 2 each time. Since we add x amount of money for every inch, and we have 480 inches, 480*x=480*25/6=2000 cents=2000/100=20 dollars is our answer

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If e = 9 cm and f = 40 cm, what is the length of g?

rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0

2 years ago

Determine if each of the following sets is a subspace of ℙn, for an appropriate value of n. Type "yes" or "no" for each answer.

xxMikexx [17]

Answer:

1. Yes.

2. No.

3. Yes.

Step-by-step explanation:

Consider the following subsets of Pn given by

1.Let W1 be the set of all polynomials of the form $p(t)=at^2$ , where a is in ℝ.

2.Let W2 be the set of all polynomials of the form $p(t)=t^2+a$ , where a is in ℝ.

3. Let W3 be the set of all polynomials of the form $p(t)=at^2+at$ , where a is in ℝ.

Recall that given a vector space V, a subset W of V is a subspace if the following criteria hold:

- The 0 vector of V is in W.

- Given v,w in W then v+w is in W.

- Given v in W and a a real number, then av is in W.

So, for us to check if the three subsets are a subset of Pn, we must check the three criteria.

- First property:

Note that for W2, for any value of a, the polynomial we get is not the zero polynomial. Hence the first criteria is not met. Then, W2 is not a subspace of Pn.

For W1 and W3, note that if a= 0, then we have p(t) =0, so the zero polynomial is in W1 and W3.

- Second property:

W1. Consider two elements in W1, say, consider a,b different non-zero real numbers and consider the polynomials

$p_1 (t) = at^2, p_2(t)=bt^2$ .

We must check that p_1+p_2(t) is in W1.

Note that

$p_1(t)+p_2(t) = at^2+bt^2 = (a+b)t^2$

Since a+b is another real number, we have that p1(t)+p2(t) is in W1.

W3. Consider two elements in W3. Say $p_1(t) = a(t^2+t), p_2(t)= b(t^2+t)$ . Then

$p_1(t) + p_2(t) = a(t^2+t) + b(t^2+t) = (a+b) (t^2+t)$

So, again, p1(t)+p2(t) is in W3.

- Third property.

W1. Consider an element in W1 $p(t) = at^2$ and a real scalar b. Then

$bp(t) = b(at^2) = (ba)t^2)$ .

Since (ba) is another real scalar, we have that bp(t) is in W1.

W3. Consider an element in W3 $p(t) = a(t^2+t)$ and a real scalar b. Then

$bp(t) = b(a(t^2+t)) = (ba)(t^2+t)$ .

Since (ba) is another real scalar, we have that bp(t) is in W3.

After all,

W1 and W3 are subspaces of Pn for n= 2

and W2 is not a subspace of Pn.

6 0

2 years ago

Karina read a total of 20 2/4 pages in her science and social studies books combined she read 12 3/4 pages in her science book h

wlad13 [49]

Answer:

8 1/4

Step-by-step explanation:

20 2/4

12 3/4

__________

8 1/4

4 0

2 years ago

Read 2 more answers

Mrs. Kermit has 29 markers. She gives 12 markers to Mr. Cooke and divides the rest among 5 other teachers. If each of the teache

romanna [79]

Answer: 2 markers.

Step-by-step explanation:

1. You know that she gives 12 markers to Mr. Cooke, then the rest among is:

29 markers-12 markers=17 markers

2. She divides the rest among 5 other teachers and each one of them get the same number of markers. So, you need to divide 17 markers by 5 teachers as following:

17 markers/5=3.4 markers

3. But the number of marker each one teacher has can't be a decimal number, so this number must be: 3 markers for each teacher.

3. The number of markers that will be left over is:

17 markers-(5*3 markers)=2 markers

8 0

2 years ago

Last year,Mark was 46 inches tall.This year,Marks height is 3 inches less than peters height.Peter is 51 inches tall.How tall is

In-s [12.5K]

Im not sure abbout the equations... but Mark is 48 inches, cuz it says; He WAS 46 in. tall. this year, amrks height is 3 inches LESS than peters height. So now, peter is 51 in. tall How tall is mark NOW? So u just have to minus 51-3 = 48!

7 0

2 years ago

Read 2 more answers