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damaskus [11]
2 years ago
6

What is the greatest common factor of 60x4y7, 45x5y5, and 75x3y? 5xy 15x3y 45x3y5 75x5y7

Mathematics
2 answers:
Rasek [7]2 years ago
8 0

Answer: 15x3y

Step-by-step explanation:

We rewrite the expressions by using factorisation method of their primes. This will give:

60x4y7= 2×2×3×5×x×x3×y×y6

45x5y5= 3×3×5×x×x4×y×y4

75x3y= 3×5×5×x×x2×y

Common factors= 3 × 5 × x3 × y

= 15x3y

Pepsi [2]2 years ago
6 0
I believe it’s 5xy since all the numbers are factors of five and since each number contains the variables xy.
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my class collected 389 milk jugs. We used 40 jugs. We gave 30 milk to the first graders. how many milk jugs did we have?
BartSMP [9]
We will just do the following steps:-

389 - 40 = 349
349 - 30 = 319

So, in the end your class had 319 milk jugs left.

Hope I helped ya!! 
8 0
2 years ago
A set of data points has a line of best fit of y=2.5x-1.5
castortr0y [4]

To solve this problem you must apply the proccedure shown below:

1- You must apply the following formula:

R=yo-yp

WhereR is the residual, yo is the observed value y and yp is the predicted value y.

2- You only need to substitute the x=5 into the equation y=2.5x-1.5 and then, you must apply the formula for calculate the residual:

y=2.5(5)-1.5\\ y=11

R=12-11\\ R=1

The answer is: The residual is 1

7 0
2 years ago
Read 2 more answers
All of the following are equivalent except _____. A:5 over 4. B:1.25. C:12.5%. D:125%.
earnstyle [38]
Hello, there!

5/4 = 1.25

So, we know that the answer is not A or B.


1.25 = 125% 

Now, we know that the answer is not D ether.

So, the answer must be C.


I hope I helped!

Let me know if you need anything else!

~ Zoe


3 0
2 years ago
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Forty students are in the science club. Of those, 45% are girls. This percent increases to 56% after new girls join the club. Ho
Gekata [30.6K]
Around 22-23 create a function and input these to find the exact

6 0
2 years ago
The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi
andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0
2 years ago
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