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Diano4ka-milaya [45]
2 years ago
7

In how many ways can 3 Americans, 4 Frenchmen, 4 Danes and 2 Italians be seated in a row so that those of the same nationality s

it together?
Mathematics
2 answers:
kaheart [24]2 years ago
4 0
Answer (13 of the original arrangements are duplicates now, as AAAF F F FDDDDCC, AAF F F FDDDDCCA, ..., CAAAF F F FDDDDC are identical): 900900/13 = 69300.
miskamm [114]2 years ago
3 0

Answer:

165888

Step-by-step explanation:

Given,

Number of americans = 3,

Total way of seating americans in 3 seats = 3 !,

Number of frenchmen = 4,

Total way of seating frenchmen in 4 seats = 4 !,

Number of danes = 4

Total ways of seating danes in 4 seat = 4 !,

Also, number of Italians = 2,

Total ways of seating italians in 2 seats = 2 !,

Hence, the total ways of seating all citizens so that people with same nationality sit together  =  ( 3! × 4! × 4! × 2! ) × 4!

= 6 × 24 × 24 × 2 × 24

= 165888

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- x - y - z = - 8 ------- (1)
- 4x + 4y + 5z = 7 -------- (2)
2x + 2z = 4 --------- (3)

From (3): x + z = 2
                      x = 2 - z --------- (4)

Substitute (4) into (1),
- x - y - z = - 8
- (2-z) - y - z = - 8
- 2 + z - y - z = -8
- 2 - y = - 8
2 + y = 8
Therefore, y = 6

Substitute y = 6 and (4) into (2),
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- 4(2 - z) + 4(6) + 5z = 7
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9z + 16 = 7
9z = - 9
Therefore, z = - 9

Substitute z = - 9 into (4),
x = 2 - z
x = 2 - (-9)
x = 2 + 9
Therefore x = 11

Solution:
x = 11
y = 6
z = -9
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2 years ago
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